如何确定函数的命名空间? [英] How do you determine the namespace of a function?

问题描述

给定一个函数，如何确定它来自哪个命名空间?

Given a function, how do you determine which namespace it has come from?

例如，如果我在命令提示符下键入 mean.default，则输出包括它位于基本包中的事实.我希望能够执行 getNamespace(mean.default) 之类的操作并让它返回base"(或实际的基本环境).

For example, if I type mean.default at the command prompt, the output includes the fact that it is in the base package. I want to be able to do something like getNamespace(mean.default) and have it return "base" (or the actual base environment).

有一个 getNamespace 函数，但似乎只接受包名而不是函数名.

There is a getNamespace function but seems to only accept package names rather than function names.

print.function 使用内部代码来检索命名空间.我在 src/main/print.c 中浏览了 do_printfunction 但后来放弃了.

print.function uses internal code to retrieve the namespace. I got as far as browsing do_printfunction in src/main/print.c but then gave up.

推荐答案

我最近了解到 find() 似乎就是这样做的.

I very recently learned about find() which seems to do just this.

R> find("ls")
[1] "package:base"
R> find("na.locf")
[1] "package:zoo"

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