discord.py 音乐机器人:如何结合播放和队列命令 [英] discord.py Music Bot: How to Combine a Play and Queue Command

问题描述

您好，我正在尝试创建一个音乐机器人，但我想要它，以便我可以使用相同的命令播放音乐并将其他音乐添加到队列中.我试过这样做，但我无法让它工作.以下是 play 和 queue 是两个独立命令的代码:

Hello I'm trying to create a music bot but I want it so I can play music and add additional music to a queue with the same command. I've tried to do this but I can't get it to work. Here's the code with play and queue being two separate commands:

@bot.command(pass_context=True)
async def join(ctx):
    await bot.join_voice_channel(bot.get_channel('487315853482786820'))


@bot.command(pass_context=True)
async def leave(ctx):
    voice_client = bot.voice_client_in(ctx.message.server)
    await voice_client.disconnect()


players = {}
queues = {}


def check_queue(id):
    if queues[id] != []:
        player = queues[id].pop(0)
        players[id] = player
        player.start()


@bot.command(pass_context=True)
async def play(ctx, url):
    server = ctx.message.server
    voice_client = bot.voice_client_in(server)
    player = await voice_client.create_ytdl_player(url, after=lambda: check_queue(server.id))
    players[server.id] = player
    player.start()


@bot.command(pass_context=True)
async def queue(ctx, url):
    server = ctx.message.server
    voice_client = bot.voice_client_in(server)
    player = await voice_client.create_ytdl_player(url, after=lambda: check_queue(server.id))

    if server.id in queues:
        queues[server.id].append(player)
    else:
        queues[server.id] = [player]
    await bot.say('Video queued.')


@bot.command(pass_context=True)
async def pause(ctx):
    id = ctx.message.server.id
    players[id].pause()


@bot.command(pass_context=True)
async def stop(ctx):
    id = ctx.message.server.id
    players[id].stop()


@bot.command(pass_context=True)
async def resume(ctx):
    id = ctx.message.server.id
    players[id].resume()

推荐答案

您需要某种队列系统，其中歌曲请求存储在队列中，并且需要一个循环来检查队列中是否有任何项目，并抓取第一个项目队列(如果可用).如果队列中没有歌曲，则循环等待直到添加歌曲.您可以使用 asyncio.Queue() 和 asyncio.Event() 来执行此操作.

You need some sort of queue system where song requests are stored in the queue and a loop that checks if any item is in the queue, grabbing the first item in the queue if it's available. If no songs are in the queue, then the loop waits until a song is added. You can use asyncio.Queue() and asyncio.Event() to do this.

import asyncio
from discord.ext import commands

client = commands.Bot(command_prefix='!')
songs = asyncio.Queue()
play_next_song = asyncio.Event()


@client.event
async def on_ready():
    print('client ready')


async def audio_player_task():
    while True:
        play_next_song.clear()
        current = await songs.get()
        current.start()
        await play_next_song.wait()


def toggle_next():
    client.loop.call_soon_threadsafe(play_next_song.set)


@client.command(pass_context=True)
async def play(ctx, url):
    if not client.is_voice_connected(ctx.message.server):
        voice = await client.join_voice_channel(ctx.message.author.voice_channel)
    else:
        voice = client.voice_client_in(ctx.message.server)

    player = await voice.create_ytdl_player(url, after=toggle_next)
    await songs.put(player)

client.loop.create_task(audio_player_task())

client.run('token')

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