首次完成 Discord Bot 后如何播放下一首歌曲 [英] How to play the next Song after first finished Discord Bot

问题描述

我正在尝试使用 discord.py 创建一个 Discord 音乐机器人，我是 Python 新手.我不知道如何让 Bot 自动播放下一首歌曲.我尝试了很多不同的东西.这是我当前播放一首歌曲的代码:

I'm trying to create a Discord music Bot with discord.py, I'm new to Python. I don't know how to let the Bot automatically play the next song. I tried many different things. This is my current code for playing one song:

vc.play(discord.FFmpegPCMAudio(executable="C:/FFmpeg/bin/ffmpeg.exe", source=sound + ".mp3"))
await message.channel.send("Spiele nun " + str(sound) +"weiter")

使用上面的代码我没有遇到问题.

With the above code I didn't get a problem.

推荐答案

您应该使用 FFmpegPCMAudio 函数的 after 参数.此参数接受一个可调用对象作为参数，并在当前歌曲结束时执行它.

You should use the after parameter of the FFmpegPCMAudio function. This parameter takes a callable as an argument and executes it when the current song is over.

• 首先，您必须创建一个歌曲队列变量:

song_queue = []

• 然后，您必须更改 play() 函数:

source = sound + '.mp3'
soung_queue.append(source)
if not vc.is_playing():
    vc.play(discord.FFmpegPCMAudio(source=source, after=lambda e: play_next(ctx))
    await ctx.send("Now playing...")
else:
    await ctx.send('Song queued')

• 最后，你必须创建一个 play_next() 函数:

import asyncio

def play_next(ctx, source):
    if len(self.song_queue) >= 1:
        del self.song_queue[0]
        vc = get(self.bot.voice_clients, guild=ctx.guild)
        vc.play(discord.FFmpegPCMAudio(source=source, after=lambda e: play_next(ctx))
        asyncio.run_coroutine_threadsafe(ctx.send("No more songs in queue."))

您可以随意命名 play_next() 函数.
如果您希望您的机器人因为它播放声音的时间太长而断开连接，请将 play_next() 函数更改为:

You can name the play_next() function whatever you want.
If you want your bot to disconnect because it's been too long since it was playing sound, change the play_next() function to :

import asyncio

def play_next(ctx, source):
    vc = get(self.bot.voice_clients, guild=ctx.guild)
    if len(self.song_queue) >= 1:
        del self.song_queue[0]
        vc.play(discord.FFmpegPCMAudio(source=source, after=lambda e: play_next(ctx))
    else:
        asyncio.sleep(90) #wait 1 minute and 30 seconds
        if not vc.is_playing():
            asyncio.run_coroutine_threadsafe(vc.disconnect(ctx), self.bot.loop)
            asyncio.run_coroutine_threadsafe(ctx.send("No more songs in queue."))
            

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