在 Excel VBA 代码中处理 XMLHttp 响应中的 JSON 对象 [英] Handle JSON Object in XMLHttp response in Excel VBA Code

问题描述

我需要处理一个 JSON 对象，它是 Excel VBA 中 XMLHTTPRequest 的响应.我写了下面的代码，但它不起作用:

 Dim sc As Object设置 sc = CreateObject("ScriptControl")sc.Language = "JScript"将 strURL 作为字符串调暗:strURL = "blah blah"暗淡的strRequest昏暗 XMLhttp:设置 XMLhttp = CreateObject("msxml2.xmlhttp")作为字符串的暗淡响应XMLhttp.Open "POST", strURL, FalseXMLhttp.setrequestheader "Content-Type", "application/x-www-form-urlencoded"XMLhttp.send strRequest响应 = XMLhttp.responseTextsc.Eval ("JSON.parse('" + response + "')")

我在 Set sc = CreateObject("ScriptControl") 行中收到错误 Run-time error '429' ActiveX component can't create objectp>

一旦我们解析了 JSON 对象，你如何访问 JSON 对象的值?

附:我的 JSON 对象示例:{"Success":true,"Message":"Blah blah"}

解决方案

代码从 nseindia 站点获取数据，该数据在 responseDiv 元素中以 JSON 字符串的形式出现.

必填参考文献

我用过的3个类模块

• cJSONScript
• cStringBuilder
• JSON

(我从 中选择了这些类模块这里)

您可以从这个链接下载文件

标准模块

Const URl As String = "http://www.nseindia.com/live_market/dynaContent/live_watch/get_quote/GetQuote.jsp?symbol=ICICIBANK"子 xmlHttp()将 xmlHttp 调暗为对象设置 xmlHttp = CreateObject("MSXML2.ServerXMLHTTP.6.0")xmlHttp.Open "GET", URl &"&rnd=" &WorksheetFunction.RandBetween(1, 99), FalsexmlHttp.setRequestHeader "内容类型", "文本/xml"xmlHttp.send将 html 调暗为 MSHTML.HTMLDocument设置 html = 新建 MSHTML.HTMLDocumenthtml.body.innerHTML = xmlHttp.ResponseText将 divData 调暗为对象设置 divData = html.getElementById("responseDiv")'?divData.innerHTML' 这里你会得到一个字符串，它是一个 JSON 数据将 strDiv 作为字符串，startVal As Long，endVal As LongstrDiv = divData.innerHTMLstartVal = InStr(1, strDiv, "数据", vbTextCompare)endVal = InStr(startVal, strDiv, "]", vbTextCompare)strDiv = "{" &Mid(strDiv, startVal - 1, (endVal - startVal) + 2) &}"将 JSON 暗淡为新 JSON暗淡为对象设置 p = JSON.parse(strDiv)我 = 1对于 p("data")(1) 中的每个项目单元格(i, 1) = 项目单元格(i，2)= p(数据")(1)(项目)我 = 我 + 1下一个结束子

I need to handle a JSON Object which is the response of XMLHTTPRequest in Excel VBA. I wrote the code below, but it doesn't work:

  Dim sc As Object
  Set sc = CreateObject("ScriptControl")
  sc.Language = "JScript"

  Dim strURL As String: strURL = "blah blah"

  Dim strRequest
  Dim XMLhttp: Set XMLhttp = CreateObject("msxml2.xmlhttp")
  Dim response As String

  XMLhttp.Open "POST", strURL, False
  XMLhttp.setrequestheader "Content-Type", "application/x-www-form-urlencoded"
  XMLhttp.send strRequest
  response = XMLhttp.responseText
  sc.Eval ("JSON.parse('" + response + "')")

I am getting the error Run-time error '429' ActiveX component can't create object in the line Set sc = CreateObject("ScriptControl")

Once we parsed the JSON Object, how do you access the values of the JSON Object?

P.S. My JSON Object sample: {"Success":true,"Message":"Blah blah"}

解决方案

The code gets the data from nseindia site which comes as a JSON string in responseDiv element.

Required References

3 Class Module i have used

• cJSONScript
• cStringBuilder
• JSON

(I have picked these class modules from here)

You may download the file from this link

Standard Module

Const URl As String = "http://www.nseindia.com/live_market/dynaContent/live_watch/get_quote/GetQuote.jsp?symbol=ICICIBANK"
Sub xmlHttp()

    Dim xmlHttp As Object
    Set xmlHttp = CreateObject("MSXML2.ServerXMLHTTP.6.0")
    xmlHttp.Open "GET", URl & "&rnd=" & WorksheetFunction.RandBetween(1, 99), False
    xmlHttp.setRequestHeader "Content-Type", "text/xml"
    xmlHttp.send

    Dim html As MSHTML.HTMLDocument
    Set html = New MSHTML.HTMLDocument
    html.body.innerHTML = xmlHttp.ResponseText

    Dim divData As Object
    Set divData = html.getElementById("responseDiv")
    '?divData.innerHTML
    ' Here you will get a string which is a JSON data

    Dim strDiv As String, startVal As Long, endVal As Long
    strDiv = divData.innerHTML
    startVal = InStr(1, strDiv, "data", vbTextCompare)
    endVal = InStr(startVal, strDiv, "]", vbTextCompare)
    strDiv = "{" & Mid(strDiv, startVal - 1, (endVal - startVal) + 2) & "}"


    Dim JSON As New JSON

    Dim p As Object
    Set p = JSON.parse(strDiv)

    i = 1
    For Each item In p("data")(1)
       Cells(i, 1) = item
       Cells(i, 2) = p("data")(1)(item)
        i = i + 1
    Next

 End Sub

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