如何通过 Selenium 在网页中捕获 WebElement 的屏幕截图，而不是整个屏幕或页面 [英] How to capture screenshot of a WebElement within a webpage but not the entire screen or page through Selenium

问题描述

我必须捕获特定网站图像的屏幕截图.也许这是整个屏幕 20% 的折扣，我使用了下面的代码，它正在捕获整个屏幕.这对我解决问题没有帮助.

WebDriver driver = new FirefoxDriver();driver.get("http://www.google.com/");文件 scrFile = ((TakesScreenshot)driver).getScreenshotAs(OutputType.FILE);FileUtils.copyFile(scrFile, new File("c:\tmp\screenshot.png"));

解决方案

根据您的代码试验 getScreenshotAs() 方法将截取整个页面.

要在特定网页中捕获 WebElement 的屏幕截图，您可以使用导入 ashot-1.4 的 AShot() 方法.4.jar 同时使用 Selenium Java Client v3.14.0、ChromeDriver v2.41、Chrome v 68.0.p><块引用>

注意:来自 ashot-1.4.4.jar 的 AShot() 方法仅适用于

I have to capture a screenshot of an image of a particular website. Maybe this is 20% off entire screen, I have used below code, it is capturing the entire screen. Which is not helping me to solve the problem.

WebDriver driver = new FirefoxDriver();
driver.get("http://www.google.com/");
File scrFile = ((TakesScreenshot)driver).getScreenshotAs(OutputType.FILE);
FileUtils.copyFile(scrFile, new File("c:\tmp\screenshot.png"));

解决方案

As per your code trials getScreenshotAs() method will take the screenshot of the entire page.

To capture the screenshot of an WebElement within a particular webpage you can use the AShot() method importing ashot-1.4.4.jar while working with Selenium Java Client v3.14.0, ChromeDriver v2.41, Chrome v 68.0.

Note: AShot() method from ashot-1.4.4.jar works only with jQuery enabled Web Applications.

So as the website http://www.google.com/ is not jQuery enabled AShot() method from ashot-1.4.4.jar won't be able to take the required screenshot.

As an example we will take a snapshot from the website https://jquery.com/.

• Code Block:

  package aShot;
  
  import java.io.File;
  
  import javax.imageio.ImageIO;
  
  import org.openqa.selenium.By;
  import org.openqa.selenium.WebDriver;
  import org.openqa.selenium.WebElement;
  import org.openqa.selenium.chrome.ChromeDriver;
  import org.openqa.selenium.chrome.ChromeOptions;
  import org.openqa.selenium.support.ui.ExpectedConditions;
  import org.openqa.selenium.support.ui.WebDriverWait;
  
  import ru.yandex.qatools.ashot.AShot;
  import ru.yandex.qatools.ashot.Screenshot;
  
  public class ashot_google_homepage_logo {
  
      public static void main(String[] args) throws Exception {
  
          System.setProperty("god.bless.you", "C:\Utility\BrowserDrivers\chromedriver.exe");
          ChromeOptions options = new ChromeOptions();
          options.addArguments("start-maximized");
          options.addArguments("disable-infobars");
          options.addArguments("--disable-extensions"); 
          WebDriver driver =  new ChromeDriver(options);
          driver.get("https://jquery.com/");
          WebElement myWebElement = new WebDriverWait(driver, 20).until(ExpectedConditions.elementToBeClickable(By.xpath("//h3[contains(.,'Lightweight Footprint')]")));
          Screenshot myScreenshot = new AShot().takeScreenshot(driver, myWebElement);
          ImageIO.write(myScreenshot.getImage(),"PNG",new File("./Screenshots/elementScreenshot.png"));
          driver.quit();
      }
  }
  

• Screenshot:

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Reference

You can find a detailed discussion in How to take screenshot with Selenium WebDriver

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