在获取所有链接时，忽略循环中的注销链接并继续在 selenium java 中导航 [英] While fetching all links,Ignore logout link from the loop and continue navigation in selenium java

问题描述

我正在获取页面中的所有链接并导航到所有链接.其中一个链接是注销.如何跳过/忽略循环中的注销链接?

I am fetching all the links in the page and navigating to all links. In that one of the link is Logout. How do i skip/ignore Logout link from the loop?

我想跳过注销链接并继续

I want to skip Logout link and proceed

列出 demovar=driver.findElements(By.tagName("a"));System.out.println(demovar.size());

List demovar=driver.findElements(By.tagName("a")); System.out.println(demovar.size());

   ArrayList<String> hrefs = new ArrayList<String>(); //List for storing all href values for 'a' tag

      for (WebElement var : demovar) {
          System.out.println(var.getText()); // used to get text present between the anchor tags
          System.out.println(var.getAttribute("href"));
          hrefs.add(var.getAttribute("href")); 
          System.out.println("*************************************");
      }

      int logoutlinkIndex = 0;

      for (WebElement linkElement : demovar) {
               if (linkElement.getText().equals("Log Out")) {
                           logoutlinkIndex = demovar.indexOf(linkElement);
                           break;
                }

      }

      demovar.remove(logoutlinkIndex);

      //Navigating to each link
      int i=0;
      for (String href : hrefs) {
          driver.navigate().to(href);
          System.out.println((++i)+": navigated to URL with href: "+href);
          Thread.sleep(5000); // To check if the navigation is happening properly.
          System.out.println("+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++");

推荐答案

如果您想从循环中省略 Logout 链接，而不是将 List 创建为 driver.findElements(By.tagName("a")); 作为替代方案，您可以使用:

If you want to leave out the Logout link from the loop instead of creating the List as driver.findElements(By.tagName("a")); as an alternative you can use:

driver.findElements(By.xpath("//a[not(contains(.,'Log Out'))]"));

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参考

您可以在以下位置找到一些相关讨论:

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Reference

You can find a couple of relevant discussions in:

• 量角器条件选择器
• 如何定位按钮通过 Python 使用 Selenium 的元素
• 什么确实 contains(., 'some text') 是指在 Selenium 中使用的 xpath 内
• xpath中的dot(.)如何在识别元素和匹配文本时采取多种形式

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