获取当前日期，给定 PHP 中的时区? [英] Get current date, given a timezone in PHP?

问题描述

我想在 PHP 中以 Paul Eggert 格式(America/New_York)的时区获取今天的日期?

I want to get todays date given a time zone in Paul Eggert format(America/New_York) in PHP?

推荐答案

其他答案设置系统中所有日期的时区.如果您想为用户支持多个时区，这并不总是有效.

The other answers set the timezone for all dates in your system. This doesn't always work well if you want to support multiple timezones for your users.

这是简短的版本:

<?php
$date = new DateTime("now", new DateTimeZone('America/New_York') );
echo $date->format('Y-m-d H:i:s');

适用于 PHP >= 5.2.0

Works in PHP >= 5.2.0

支持的时区列表:php.net/manual/en/timezones.php

这是一个有现有时间并通过用户设置设置时区的版本

Here's a version with an existing time and setting timezone by a user setting

<?php

$usersTimezone = 'America/New_York';
$date = new DateTime( 'Thu, 31 Mar 2011 02:05:59 GMT', new DateTimeZone($usersTimezone) );
echo $date->format('Y-m-d H:i:s');

<小时>

这里有一个更详细的版本，可以更清楚地展示这个过程

---

Here is a more verbose version to show the process a little more clearly

<?php

// Date for a specific date/time:
$date = new DateTime('Thu, 31 Mar 2011 02:05:59 GMT');

// Output date (as-is)
echo $date->format('l, F j Y g:i:s A');     

// Output line break (for testing)
echo "
<br />
";

// Example user timezone (to show it can be used dynamically)
$usersTimezone = 'America/New_York';

// Convert timezone
$tz = new DateTimeZone($usersTimezone);
$date->setTimeZone($tz);

// Output date after 
echo $date->format('l, F j Y g:i:s A');

<小时>

库

• Carbon — 一个非常流行的日期库.
• Chronos — 专注于不变性的 Carbon 替代品.请参阅下文，了解为什么这很重要.
• jenssegers/date — Carbon 的扩展，增加了多语言支持.

---

Libraries

• Carbon — A very popular date library.
• Chronos — A drop-in replacement for Carbon focused on immutability. See below on why that's important.
• jenssegers/date — An extension of Carbon that adds multi-language support.

我确信还有许多其他可用的库，但这些是我熟悉的一些.

当你在这里的时候，让我为你省去一些未来的头痛.假设您要计算从今天开始的 1 周和从今天开始的 2 周.你可能会写一些类似的代码:

While you're here, let me save you some future headache. Let's say you want to calculate 1 week from today and 2 weeks from today. You might write some code like:

<?php

// Create a datetime (now, in this case 2017-Feb-11)
$today = new DateTime();

echo $today->format('Y-m-d') . "
<br>";
echo "---
<br>";

$oneWeekFromToday = $today->add(DateInterval::createFromDateString('7 days'));
$twoWeeksFromToday = $today->add(DateInterval::createFromDateString('14 days'));

echo $today->format('Y-m-d') . "
<br>";
echo $oneWeekFromToday->format('Y-m-d') . "
<br>";
echo $twoWeeksFromToday->format('Y-m-d') . "
<br>";
echo "
<br>";

输出:

2017-02-11 
--- 
2017-03-04 
2017-03-04 
2017-03-04

嗯...这不是我们想要的.在 PHP 中修改传统的 DateTime 对象不仅会返回更新的日期，还会修改原始对象.

Hmmmm... That's not quite what we wanted. Modifying a traditional DateTime object in PHP not only returns the updated date but modifies the original object as well.

这就是 DateTimeImmutable 的用武之地.

This is where DateTimeImmutable comes in.

$today = new DateTimeImmutable();

echo $today->format('Y-m-d') . "
<br>";
echo "---
<br>";

$oneWeekFromToday = $today->add(DateInterval::createFromDateString('7 days'));
$twoWeeksFromToday = $today->add(DateInterval::createFromDateString('14 days'));

echo $today->format('Y-m-d') . "
<br>";
echo $oneWeekFromToday->format('Y-m-d') . "
<br>";
echo $twoWeeksFromToday->format('Y-m-d') . "
<br>";

输出:

2017-02-11 
--- 
2017-02-11 
2017-02-18 
2017-02-25 

在第二个示例中，我们得到了预期的日期.通过使用 DateTimeImmutable 而不是 DateTime，我们可以防止意外的状态突变并防止潜在的错误.

In this second example, we get the dates we expected back. By using DateTimeImmutable instead of DateTime, we prevent accidental state mutations and prevent potential bugs.

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