Python-ldap:是否可以在不显式写入密码的情况下进行绑定? [英] Python-ldap: is it possible to bind without explicitly writing the password?

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问题描述

编写一个 Python 脚本,我想知道是否可以在不以明文形式写入密码的情况下绑定到 LDAP 服务器,如下例所示:

Writing a Python script, I would like to know if it is possible to bind to an LDAP server without writing the password in plaintext, like in this example:

import ldap

l = ldap.open("myserver")
username = "cn=Manager, o=mydomain.com"

## I don't want to write the password here in plaintext
password  = "secret"

l.simple_bind(username, password)

推荐答案

解密名为.credentials"的文件的示例函数.这当然会有一个单独的脚本,在尝试使用它之前首先将凭据加密到文件中.

Example Function for decrypting a file called '.credentials'. This would of course have a seporate script to encrypt the credentials to a file in the first place prior to trying to use it.

所以你会调用这个函数:

So you would call this function:

username, password = decrypt()

l.simple_bind(username, password)

from Crypto.Cipher import AES
import base64
from local_logging import info

def decrypt(dir_path):
    #Read '.credentials' file and return unencrypted credentials (user_decoded, pass_decoded)

    lines = [line.rstrip('
') for line in open(dir_path + '/.credentials')]

    user_encoded = lines[0]
    user_secret = lines[1]
    pass_encoded = lines[2]
    pass_secret = lines[3]

    # the character used for padding--with a block cipher such as AES, the value
    # you encrypt must be a multiple of BLOCK_SIZE in length.  This character is
    # used to ensure that your value is always a multiple of BLOCK_SIZE
    PADDING = '{'

    DecodeAES = lambda c, e: c.decrypt(base64.b64decode(e)).rstrip(PADDING)

    # create a cipher object using the random secret
    user_cipher = AES.new(user_secret)
    pass_cipher = AES.new(pass_secret)

    # decode the encoded string
    user_decoded = DecodeAES(user_cipher, user_encoded)
    pass_decoded = DecodeAES(pass_cipher, pass_encoded)

    return (user_decoded, pass_decoded)

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