通过发件人在 Swift 上获取按钮按下的 id [英] Get button pressed id on Swift via sender

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本文介绍了通过发件人在 Swift 上获取按钮按下的 id的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

所以我有一个带有 3 个按钮的情节提要

有没有办法为每个按钮获取某种标识符?

顺便说一句,它们是图像,所以它们没有标题.

@IBAction func mainButton(sender: UIButton) {打印(发件人)}

解决方案

您可以在情节提要中为每个按钮设置一个 tag.然后你可以这样识别它们:

@IBAction func mainButton(sender: UIButton) {println(sender.tag)}

为了提高可读性,您可以定义一个枚举,其值对应于所选标签.因此,如果您为按钮设置 012 等标签,则可以在类声明上方执行以下操作:

枚举 SelectedButtonTag: Int {案例一案例二案例三}

然后您将拥有以下内容,而不是处理硬编码的值:

@IBAction func mainButton(sender: UIButton) {切换发件人.tag {案例 SelectedButtonTag.First.rawValue:println("当第一个按钮被点击时做一些事情")案例 SelectedButtonTag.Second.rawValue:println("当第二个按钮被点击时做一些事情")案例 SelectedButtonTag.Third.rawValue:println("当第三个按钮被点击时做某事")默认:println("默认")}}

So I have a storyboard with 3 buttons I want to just create 1 action for all those 3 buttons and decide what to do based on their label/id...

Is there a way to get some kind of identifier for each button?

By the way they are images, so they don't have a title.

@IBAction func mainButton(sender: UIButton) {
    println(sender)
}

解决方案

You can set a tag in the storyboard for each of the buttons. Then you can identify them this way:

@IBAction func mainButton(sender: UIButton) {
    println(sender.tag)
}

EDIT: For more readability you can define an enum with values that correspond to the selected tag. So if you set tags like 0, 1, 2 for your buttons, above your class declaration you can do something like this:

enum SelectedButtonTag: Int {
    case First
    case Second
    case Third
}

And then instead of handling hardcoded values you will have:

@IBAction func mainButton(sender: UIButton) {
    switch sender.tag {
        case SelectedButtonTag.First.rawValue:
            println("do something when first button is tapped")
        case SelectedButtonTag.Second.rawValue:
            println("do something when second button is tapped")
        case SelectedButtonTag.Third.rawValue:                       
            println("do something when third button is tapped")
        default:
            println("default")
    }
}

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