如何删除文件名创建ZIP文件时的GUID？ [英] How to remove guid from file name when creating zip file?

问题描述

当用户上传多个文档，我自己存储的文件在我的项目是这样的：

When user uploads multiple documents I am storing their files in my project like this:

 Guid id;
 id = Guid.NewGuid();
 string filePath = Path.Combine(HttpContext.Server.MapPath("../Uploads"),
 Path.GetFileName(id + item.FileName));
 item.SaveAs(filePath);

所以文件都在我的项目保存这样的：

So files are saved like this in my project:

1. 1250a2d5-cd40-4bcc-a979-9d6f2cd62b9fLog.txt


2. bdb31966-e3c4-4344-B02C-305c0eb0fa0aLogging.txt

现在创建压缩文件时，我收到此文件同名的压缩zip文件的时候，但我不经过用户下载的文件我的文件名希望GUID。

Now when creating zip files I am getting same name of this files when extracting zip files but I don't want guid in my file name after user downloads file.

不过，我曾试图remove从我的文件名的GUID，但得到的错误 System.IO.FileNotFoundException 。

However I have tried to remove guid from my file name but getting error System.IO.FileNotFoundException.

这是我的code：

using (var zip = new ZipFile())
{
    var str = new string[] { "1250a2d5-cd40-4bcc-a979-9d6f2cd62b9fLog.txt", "bdb31966-e3c4-4344-b02c-305c0eb0fa0aLogging.txt" }; //file name are Log.txt and Logging.txt
    string[] str1 = str .Split(',');
    foreach (var item in str1)
    {
        string filePath = Server.MapPath("~/Uploads/" + item.Substring(36));//as guid are of 36 digits
        zip.AddFile(filePath, "files");
    }
    zip.Save(memoryStream);//Getting error here
}

任何人可以帮助我呢？

Can anybody help me with this?

推荐答案

ZipFile中抛出一个异常，因为它无法找到磁盘上的文件，因为你给了它一个不存在的文件的名称（通过执行.Substring（））。为了使它工作，你就必须使用File.Copy文件与新的文件名重命名，然后给出相同的文件名Zip.AddFile（）。

ZipFile is throwing an exception because it can't find the file on disk as you have given it a name of a file that does not exist (by doing a .Substring()). To make it work you would have to rename the file using File.Copy with your new file name and then give that same file name to Zip.AddFile().

  var orgFileName = "1250a2d5-cd40-4bcc-a979-9d6f2cd62b9fLog.txt";
  var newFileName = orgFileName.Substring (36);
  File.Copy (orgFileName, newFileName, true);
  zip.AddFile (newFileName);

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