Android 从 gridview 布局索引转换为行和列 [英] Android From gridview layout index convert into row and column

问题描述

如果我在网格上的某个位置的索引从 0 开始，我怎样才能将它变成一行、一列?我得到以下不正确的结果.幸运的是我知道我有多少行和列，在我的例子中是 11 x 11.

If I have index starting from 0, of a position on a grid, how can I turn that into a row, column? I'm getting incorrect results with the following. Fortunately I know how many rows and columns I have and in my case its 11 by 11.

int column = position % columns;

int row = position / columns;

推荐答案

// x : horizontal position in range [0; columns-1]
// y : vertical position in range [0; rows-1]

int x = index % columns;
int y = index / columns;
int column = x + 1;
int row = y + 1;

反转:

int index = x + y * columns;

或

int index = (column - 1) + (row - 1) * columns;

这篇关于Android 从 gridview 布局索引转换为行和列的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！