子进程通配符用法 [英] subprocess wildcard usage

问题描述

import os

import subprocess

proc = subprocess.Popen(['ls','*.bc'], stdout=subprocess.PIPE, stderr=subprocess.PIPE)

out,err = proc.communicate()

print out

这个脚本应该打印所有带有 .bc 后缀的文件，但是它返回一个空列表.如果我在命令行中手动执行 ls *.bc ，它就可以工作.在脚本中执行 ['ls','test.bc'] 也可以，但由于某种原因星号不起作用.. 有什么想法吗?

This script should print all the files with .bc suffix however it returns an empty list. If I do ls *.bc manually in the command line it works. Doing ['ls','test.bc'] inside the script works as well but for some reason the star symbol doesnt work.. Any ideas ?

推荐答案

您需要提供 shell=True 以通过 shell 解释器执行命令.但是，如果您这样做，则不能再提供一个列表作为第一个参数，因为这些参数将被引用.相反，请指定您希望将其传递给 shell 的原始命令行:

You need to supply shell=True to execute the command through a shell interpreter. If you do that however, you can no longer supply a list as the first argument, because the arguments will get quoted then. Instead, specify the raw commandline as you want it to be passed to the shell:

 proc = subprocess.Popen('ls *.bc', shell=True,
                                    stdout=subprocess.PIPE,
                                    stderr=subprocess.PIPE)

这篇关于子进程通配符用法的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！