获取 Spring Data 上按日期排序的最后记录 [英] Get last records ordered by date on Spring Data

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本文介绍了获取 Spring Data 上按日期排序的最后记录的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试在 Spring Data 存储库中定义一个方法,以获取按日期排序的表中的最后一条记录.这是我的实体:

I'm trying to define a method in a Spring Data repository to fetch the last records on a table ordered by date. This is my entity:

@Entity
public class News {

    @Id
    @GeneratedValue
    private Long id;

    @Column(nullable = false)
    private String title;

    @Column(nullable = false)
    private String text;

    private Date publicationDate;

    /* Getters and Setters */
}

这是我的存储库:

public interface NewsRepository extends JpaRepository<News, Long> {
    List<News> findFirst5OrderByPublicationDateDesc();
}

如果我尝试使用启动项目,我会收到下一个错误:

If I try to use launch the project I get the next error:

原因:org.springframework.data.mapping.PropertyReferenceException:否找到类型日期的属性描述!遍历路径:News.publicationDate.

Caused by: org.springframework.data.mapping.PropertyReferenceException: No property desc found for type Date! Traversed path: News.publicationDate.

如果我删除 Desc,我会得到:

And if I remove the Desc I get this:

原因:java.util.NoSuchElementException

Caused by: java.util.NoSuchElementException

我做错了什么?

推荐答案

原来方法的签名不正确.正确的是:

Turns out that the signature of the method was incorrect. The right one is:

findFirst5ByOrderByPublicationDateDesc()

有点令人困惑,因为在官方示例中他们有这个:

Is a little confusing because in the official samples they have this:

List<User> findTop10ByLastname(String lastname, Pageable pageable);

如您所见,那里只有一个,通常的那个.

As you can see there is only one By there, the usual one.

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