Django 小部件覆盖模板 [英] Django widget override template

问题描述

我是 django 的新手.

我想创建一个自定义小部件.

forms.py:

从 project.widgets 导入 MultiChoiceFilterWidget类 CustomSearchForm(FacetedSearchForm):测试颜色 = [uBlau"，uRot"，uGelb"]颜色 = forms.MultipleChoiceField(label=_("Color"), 选择=[(x, x) for x in TEST_COLORS],小部件=MultiChoiceFilterWidget，必需=假)

widget.py:

类 MultiChoiceFilterWidget(forms.widgets.CheckboxSelectMultiple):template_name = '项目/小部件/filter.html'option_template_name = 'ptoject/widgets/filter_option.html'

项目/小部件/filter.html:

 <h1>TEST</h1>

但它不会呈现新的模板，而是仍然呈现旧的方式.

你能给我一些建议吗?

解决方案

Django 版本

1.11:

小部件必须实现 render 方法才能渲染不同的模板:

from django.utils.safestring import mark_safe从 django.template.loader 导入 render_to_stringMultiChoiceFilterWidget 类(forms.widgets.CheckboxSelectMultiple):template_name = '项目/小部件/filter.html'def 渲染(自我，数据):...用数据做事...return mark_safe(render_to_string(self.template_name))

<小时>Django 1.11 版:

在 renderer 的文档中，我们可以找到以下内容:

<块引用>

Django 1.11 中的新功能:

在旧版本中，小部件是使用 Python 呈现的.本文档中描述的所有 API 都是新的.

查看 widget 源代码 特别是关于 Input 小部件如何扩展 Widget 类，我们可以看到您只需要按如下方式自定义小部件:

类 MultiChoiceFilterWidget(forms.widgets.CheckboxSelectMultiple):template_name = '项目/小部件/filter.html'

这是你已经拥有的.

I am new at django.

I want to create a custom widget.

forms.py:

from project.widgets import MultiChoiceFilterWidget

class CustomSearchForm(FacetedSearchForm):
    TEST_COLORS = [
        u"Blau", u"Rot", u"Gelb"
    ]

    color = forms.MultipleChoiceField(
        label=_("Color"), choices=[(x, x) for x in TEST_COLORS],
        widget=MultiChoiceFilterWidget, required=False)

widget.py:

class MultiChoiceFilterWidget(forms.widgets.CheckboxSelectMultiple):
    template_name = 'project/widgets/filter.html'
    option_template_name = 'ptoject/widgets/filter_option.html'

project/widgets/filter.html:

 <h1>TEST</h1>

But it doesn't render the new template, instead it still renders the old way.

Can you give me some tips?

解决方案

Django version < 1.11:

The widget must implement the render method in order to render a different template:

from django.utils.safestring import mark_safe
from django.template.loader import render_to_string

class MultiChoiceFilterWidget(forms.widgets.CheckboxSelectMultiple):
    template_name = 'project/widgets/filter.html'

    def render(self, data):
        ...
        Do stuff with data
        ...
        return mark_safe(render_to_string(self.template_name))

---

Django version 1.11:

In the renderer's documentation, we can find the following:

New in Django 1.11:

In older versions, widgets are rendered using Python. All APIs described in this document are new.

And by having a look at the widget source code and specifically on how the Input widget extends the Widget class, we can see that you would only need to customize your widget as follows:

class MultiChoiceFilterWidget(forms.widgets.CheckboxSelectMultiple):
    template_name = 'project/widgets/filter.html'

Which is what you have already.

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