将 JSON 解组为映射/字符串列表 [英] Unmarshal JSON to Map/List of Strings

问题描述

我想将一个 Json 解组为一个 Map/List of Strings(例如 Map>...)

I would like to unmarshal a Json to a Map/List of Strings (eg Map>...)

这是我的输入:

{"pointsOfSale": 
{"pointOfSale":[ 
{"href":"/pointsOfSale/UUID.0abc2aca-7930-4c9e-9f38-8af3d0692e04", 
"model":{"href":"/models/modelePointOfSale", 
"modelType":{"href":"/modelTypes/pointOfSale"}}, 
"source":{"href":"/sources/TEST"}, 
"attribute":[ 
{"code":"pointOfSalePhysical","value":true}, 
{"code":"mail","value":"Mail1"}, 
{"code":"adresse","value":"address1"}]}, 
{"href":"/pointsOfSale/UUID.a12e7adf-652a-4197-91bf-d4785e43f09f", 
"model":{"href":"/models/modelePointOfSale", 
"modelType":{"href":"/modelTypes/pointOfSale"}}, 
"source":{"href":"/sources/Wikeo"}, 
"attribute":[ 
{"code":"pointOfSalePhysical","value":false}, 
{"code":"mail","value":"Mail1"}, 
{"code":"adresseMateriau","value":"Material address1"}]} 
}}

我希望能够在解组后做这样的事情":

I would like to be able to do "something" like this after unmarshaling:

myJsonMapped.get("pointsOfSale").get("pointOfSale").get(0).get("source").get("href").equals("/sources/TEST") == true 

例如，使用 Gson 我们可以进行这种解码:

For instance, with Gson we can do this kind of decoding:

new Gson().fromJson(json, Map.class); 

我知道我可以用一个简单的 bean 或处理器等来做到这一点......

I know I can do this with a simple bean or processor etc...

我只是想知道我可以使用原生 JSON 骆驼组件配置更有效地做到这一点

I just want to know of I can do this more efficiently with a native JSON camel component config

我已经尝试了不同的东西:解组().json()...或者unmarshal().json(JsonLibrary.Gson, Map.class)..等等...没有成功:'(

I tried different thing already like : unmarshal().json()... or unmarshal().json(JsonLibrary.Gson, Map.class).. etc... without succes :'(

推荐答案

你可以用杰克逊做这样的事情.

You could do something like this with jackson.

<dataFormats>
  <json id="jack" library="Jackson"/>
</dataFormats>

...

<route>
  <from uri="direct:test"/>
  <unmarshal ref="jack"/>
  <process ref="something"/>
</route>

或者在java中使用gson:

Or in java with gson:

 from("foo:bar")
    .unmarshal().json(JsonLibrary.Gson,Map.class)
    .to("foo:baz");

如果你没有让它工作，请说明错误，等等.

If you're not getting it to work, please state error and so fourth.

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