在MVC4使用Ajax.BeginForm [英] Using Ajax.BeginForm in MVC4

问题描述

我有这样的事情

@using (Ajax.BeginForm("Next", "Controll", null, new AjaxOptions() { UpdateTargetId = "updateRegion", InsertionMode = InsertionMode.Replace, HttpMethod = "GET" }))
{
 <div id="updateRegion">
 @Html.Partial("_callingFromPartial", Model.List[0])
</div>
}


       @Html.RadioButtonFor(item => Model.OptionSelected, Model.IdOption, new { id = "select" + Model.IdOption })
       <label>@Model.OptionText</label>
       <input type="submit" value="Next"/>


[HttpGet]
    public ActionResult Next(Bu.Models.ChoiceQuestion itemReturn)
    {
        CurrentItem = Itens[refe+1];
        return PartialView("_callingFromPartial", CurrentItem);
    }

但它不喜欢的工作我想，我试图加载#updateRegion接下来的内容，但它显示的资源不能被发现。 ，有什么不对的？

But it's not working like I want, I'm trying to load the next content in #updateRegion, but it's showing "The resource cannot be found." , is there anything wrong with this?

推荐答案

尝试将格updateRegion表单标签内。
如： -

Try placing div "updateRegion" inside the form tag. Like :-

@using (Ajax.BeginForm("Next", "Controll", null, new AjaxOptions() { UpdateTargetId = "updateRegion", InsertionMode = InsertionMode.Replace, HttpMethod = "GET" }))
{ 
  <div id="updateRegion">
  </div>
  @Html.RadioButtonFor(item => Model.OptionSelected, Model.IdOption, new { id = "select" + Model.IdOption })
  <label>@Model.OptionText</label>
  <input type="submit" value="Next" />
}

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