我可以强制 JAXB 不转换吗?例如，当编组为 XML 时? [英] Can I force JAXB not to convert " into ", for example, when marshalling to XML?

问题描述

我有一个使用 JAXB 编组为 XML 的对象.一个元素包含一个包含引号 (") 的字符串.生成的 XML 包含 "，其中存在 ".

I have an Object that is being marshalled to XML using JAXB. One element contains a String that includes quotes ("). The resulting XML has " where the " existed.

尽管这通常是首选，但我需要我的输出匹配 legacy 系统.如何强制 JAXB 不转换 HTML 实体?

Even though this is normally preferred, I need my output to match a legacy system. How do I force JAXB to NOT convert the HTML entities?

--

感谢您的回复.但是，我从来没有看到处理程序 escape() 被调用.你能看看我做错了什么吗?谢谢！

Thank you for the replies. However, I never see the handler escape() called. Can you take a look and see what I'm doing wrong? Thanks!

package org.dc.model;

import java.io.IOException;
import java.io.Writer;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;

import org.dc.generated.Shiporder;

import com.sun.xml.internal.bind.marshaller.CharacterEscapeHandler;

public class PleaseWork {
    public void prettyPlease() throws JAXBException {
        Shiporder shipOrder = new Shiporder();
        shipOrder.setOrderid("Order's ID");
        shipOrder.setOrderperson("The woman said, "How ya doin & stuff?"");

        JAXBContext context = JAXBContext.newInstance("org.dc.generated");
        Marshaller marshaller = context.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);
        marshaller.setProperty(CharacterEscapeHandler.class.getName(),
                new CharacterEscapeHandler() {
                    @Override
                    public void escape(char[] ch, int start, int length,
                            boolean isAttVal, Writer out) throws IOException {
                        out.write("Called escape for characters = " + ch.toString());
                    }
                });
        marshaller.marshal(shipOrder, System.out);
    }

    public static void main(String[] args) throws Exception {
        new PleaseWork().prettyPlease();
    }
}

--

输出是这样的:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<shiporder orderid="Order's ID">
    <orderperson>The woman said, &quot;How ya doin &amp; stuff?&quot;</orderperson>
</shiporder>

如您所见，回调永远不会显示.(一旦我得到回调被调用，我会担心它真的做我想做的事.)

and as you can see, the callback is never displayed. (Once I get the callback being called, I'll worry about having it actually do what I want.)

--

推荐答案

我的队友找到的解决方案:

Solution my teammate found:

PrintWriter printWriter = new PrintWriter(new FileWriter(xmlFile));
DataWriter dataWriter = new DataWriter(printWriter, "UTF-8", DumbEscapeHandler.theInstance);
marshaller.marshal(request, dataWriter);

不要将 xmlFile 传递给 marshal()，而是传递知道编码和适当的转义处理程序(如果有)的 DataWriter.

Instead of passing the xmlFile to marshal(), pass the DataWriter which knows both the encoding and an appropriate escape handler, if any.

注意:由于 DataWriter 和 DumbEscapeHandler 都在 com.sun.xml.internal.bind.marshaller 包中，因此您必须引导 javac.

Note: Since DataWriter and DumbEscapeHandler are both within the com.sun.xml.internal.bind.marshaller package, you must bootstrap javac.

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