JAXB @XmlAdapter:映射 ->列表适配器?(仅限马歇尔) [英] JAXB @XmlAdapter: Map -> List adapter? (marshall only)

问题描述

我有一个 Map<String, String>.
每个人的第一个想法是将其转换为 List<Pair<String,String>> (Pair 是一个自定义类).

I have a Map<String, String>.
The first idea everyone has is to convert it to a List<Pair<String,String>> (Pair being a custom class).

我试过这样的 @XmlAdapter:

public class MapPropertiesAdapter extends XmlAdapter<List<Property>, Map<String,String>> { ... }

但我使用的 JAXB impl Eclipse MOXy 以 ClassCastException 告终——无法将 HashMap 转换为 Collection".

But Eclipse MOXy, the JAXB impl I use, ended up with a ClassCastException - "can't convert HashMap to Collection".

JAXB 是否支持这种转换?还是我忽略了一些解释为什么不是的文档部分?

Is this conversion supported by JAXB? Or did I overlook some documentation part which explains why it isn't?

PS:我想得到这样的 XML:

PS: I wanted to get XML like this:

<properties>
    <property name="protocol"/>
    <property name="marshaller"/>
    <property name="unmarshaller"/>
    <property name="timeout"/>
    ...
</properties>

我明白了，只需要使用一个中间类.也描述在在 XMLCompositeObjectMappingNodeValue.marshalSingleValue(XMLCompositeObjectMappingNodeValue.java:161) 中处理 NPEp>

I got it, only had to use an intermediate class. Also described at Handle NPE in XMLCompositeObjectMappingNodeValue.marshalSingleValue( XMLCompositeObjectMappingNodeValue.java:161)

推荐答案

不要将 Map 适配为 List，而应将其适配为具有列表属性.

Instead of adapting the Map to a List, you should adapt it to an object that has a List property.

XmlAdapter (MapPropertiesAdapter)

import java.util.*;
import java.util.Map.Entry;
import javax.xml.bind.annotation.*;
import javax.xml.bind.annotation.adapters.XmlAdapter;

public class MapPropertiesAdapter extends XmlAdapter<MapPropertiesAdapter.AdaptedProperties, Map<String, String>>{

    public static class AdaptedProperties {
        public List<Property> property = new ArrayList<Property>();
    }

    public static class Property {
        @XmlAttribute
        public String name;

        @XmlValue
        public String value;
    }

    @Override
    public Map<String, String> unmarshal(AdaptedProperties adaptedProperties) throws Exception {
        if(null == adaptedProperties) {
            return null;
        }
        Map<String, String> map = new HashMap<String, String>(adaptedProperties.property.size());
        for(Property property : adaptedProperties.property) {
            map.put(property.name, property.value);
        }
        return map;
    }

    @Override
    public AdaptedProperties marshal(Map<String, String> map) throws Exception {
        if(null == map) {
            return null;
        }
        AdaptedProperties adaptedProperties = new AdaptedProperties();
        for(Entry<String,String> entry : map.entrySet()) {
            Property property = new Property();
            property.name = entry.getKey();
            property.value = entry.getValue();
            adaptedProperties.property.add(property);
        }
        return adaptedProperties;
    }

}

域模型(根)

下面是一个带有 Map 属性的模型对象.@XmlJavaTypeAdapter 注解用于指定XmlAdapter.

Below is a model object with a Map property. The @XmlJavaTypeAdapter annotation is used to specify the XmlAdapter.

import java.util.Map;
import javax.xml.bind.annotation.*;
import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter;

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class Root {

    @XmlJavaTypeAdapter(MapPropertiesAdapter.class)
    private Map<String, String> properties;

}

演示

import java.io.File;
import javax.xml.bind.*;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(Root.class);

        Unmarshaller unmarshaller = jc.createUnmarshaller();
        File xml = new File("src/forum17024050/input.xml");
        Root root = (Root) unmarshaller.unmarshal(xml);

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(root, System.out);
    }

}

input.xml/Output

<?xml version="1.0" encoding="UTF-8"?>
<root>
    <properties>
        <property name="A">a</property>
        <property name="B">b</property>
    </properties>
</root>

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