Swift 中的 switch 语句 [英] Switch statement in Swift

问题描述

我正在学习 Swift 的语法，我想知道为什么下面的代码没有像我预期的那样工作:

I'm learning syntax of Swift and wonder, why the following code isn't working as I expect it to:

for i in 1...100{

    switch (i){
    case 1:
        Int(i%3) == 0
        println("Fizz")
    case 2:
        Int(i%5) == 0
        println("Buzz")
    default:
        println("(i)")
    }  
}

我想在每次数字可以被 3 整除(3、6、9、12 等)时打印 Fizz，并在每次可以被 5 整除时打印 Buzz.缺少哪一块拼图?

I want to print Fizz every time number is divisible by 3 (3, 6, 9, 12, etc) and print Buzz every time it's divisible by 5. What piece of the puzzle is missing?

注意:我确实使用以下方法解决了它:

Note: I did solve it using the following:

for ( var i = 0; i < 101; i++){

    if (Int(i%3) == 0){
        println("Fizz")
    }   else if (Int(i%5) == 0){
        println("Buzz")
    }   else {
        println("(i)")
    }   
}

我想知道如何使用 Switch 来解决这个问题.谢谢.

I want to know how to solve this using Switch. Thank you.

推荐答案

FizzBu​​zz 游戏的常用规则将每个 3 的倍数替换为Fizz"，将每个 5 的倍数替换为Buzz"，以及FizzBu​​zz"的和 5 的每3 个倍数.

The usual rules for the FizzBuzz game are to replace every multiple of 3 by "Fizz", every multiple of 5 by "Buzz", and every multiple of both 3 and 5 by "FizzBuzz".

这可以通过元组 (i % 3, i % 5) 上的 switch 语句来完成.请注意，_ 表示任何值":

This can be done with a switch statement on the tuple (i % 3, i % 5). Note that _ means "any value":

for i in 1 ... 100 {
    switch (i % 3, i % 5) {
    case (0, 0):
        print("FizzBuzz")
    case (0, _):
        print("Fizz")
    case (_, 0):
        print("Buzz")
    default:
        print(i)
    }
}

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