获取 WIFI 和移动数据的信号强度 [英] Get signal strength of WIFI and Mobile Data

问题描述

在我的应用程序中，我需要检查 WiFi 和移动数据的连接速度，然后进行比较，然后切换到具有最高速度的网络.

In my app I need to check the connection speed of both WiFi and Mobile Data and then compare it, then switch to which ever network has the highest speed.

• 那么我怎样才能获得wifi和手机的速度或最佳信号强度数据?
• 如何以编程方式关闭一个，然后打开另一个.

请帮帮我.一个样本会很有帮助.

Please help me out. A sample would be helpful.

推荐答案

Wifi:

WifiManager wifiManager = (WifiManager)context.getSystemService(Context.WIFI_SERVICE);
int linkSpeed = wifiManager.getConnectionInfo().getRssi();

如果是移动设备，它应该可以工作:

In case of mobile it should work:

TelephonyManager telephonyManager =        (TelephonyManager)this.getSystemService(Context.TELEPHONY_SERVICE);
CellInfoGsm cellinfogsm = (CellInfoGsm)telephonyManager.getAllCellInfo().get(0);
CellSignalStrengthGsm cellSignalStrengthGsm = cellinfogsm.getCellSignalStrength();
cellSignalStrengthGsm.getDbm();

然后你应该比较这个信号水平，如果WIFI信号更好保持打开，但如果手机更好断开wifi

Then You should compare this signal levels and if WIFI signal is better keep it turn on, but if mobile is better disconnect wifi

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