使用 Youtube AS3 Player API 时如何避免安全错误 [英] How to avoid Security Errors when using the Youtube AS3 Player API

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问题描述

我正在使用 Youtube AS3 Player API 在 Flash 项目中加载视频.加载播放器 swf 时出现这个非常烦人的错误:

I'm using the Youtube AS3 Player API to load video's in a Flash Project. I get this really annoying Error when loading the Player swf:

SecurityError: Error #2047: Security sandbox violation: parent: http://www.degoudenglimlach.be/main.swf cannot access http://www.youtube.com/[[IMPORT]]/s.ytimg.com/yt/swf/watch_as3-vflbgr4dW.swf.

我尝试在加载 swf 之前将以下内容添加到我的代码中,但没有任何区别:

I tried adding the following to my code before loading the swf but it doesn't make any difference:

Security.allowDomain("*");
Security.allowDomain("www.youtube.com");
Security.allowDomain("youtube.com");
Security.allowDomain("s.ytimg.com");
Security.allowDomain("i.ytimg.com");

任何帮助都会很棒.

这是我的完整包装类:

package be.zap.media 
{
    import flash.display.Loader;
    import flash.display.Sprite;
    import flash.events.Event;
    import flash.net.URLRequest;
    import flash.system.Security;
    import flash.system.System;

    /**
     * ...
     * @author Yens Resmann
     */
    public class ZapYoutubeVideo extends Sprite
    {
        private var ytPlayer : Object;
        private var ldr : Loader
        private static const YOUTUBE_EMBEDDED_PLAYER_URL : String = "http://www.youtube.com/v/VIDEO_ID?version=3";

        public static const PLAYER_READY : String = "playerReady";

        public static const QUALITY_SMALL : String = "small";
        public static const QUALITY_MEDIUM : String = "medium";
        public static const QUALITY_LARGE : String = "large";
        public static const QUALITY_HD720 : String = "hd720";
        public static const QUALITY_HD1080 : String = "hd1080";
        public static const QUALITY_HIGHRES : String = "highres";
        public static const QUALITY_DEFAULT : String = "default";

        public function ZapYoutubeVideo() 
        {
            Security.allowDomain("*");
            Security.allowDomain("www.youtube.com");
            Security.allowDomain("youtube.com");
            Security.allowDomain("s.ytimg.com");
            Security.allowDomain("i.ytimg.com");

            ldr = new Loader();
            ldr.contentLoaderInfo.addEventListener(Event.INIT, handleInitPlayer);
            addEventListener(Event.REMOVED_FROM_STAGE, handleRemovedFromStage);
        }

        public function initPlayer(vidId : String) 
        {
            var url : String = YOUTUBE_EMBEDDED_PLAYER_URL.split("VIDEO_ID").join(vidId);
            ldr.load(new URLRequest(url));
        }

        private function handleInitPlayer(e:Event):void 
        {
            addChild(ldr);
            ldr.contentLoaderInfo.removeEventListener(Event.INIT, handleInitPlayer);

            ldr.content.addEventListener("onReady", handlePlayerReady);
            ldr.content.addEventListener("onError", handlePlayerError);
            ldr.content.addEventListener("onStateChange", handlePlayerStageChange);
            ldr.content.addEventListener("onPlaybackQualityChange", handlePlayerQualityChange);
        }

        private function handlePlayerReady(e:Event):void 
        {
            ytPlayer = ldr.content;
            dispatchEvent(new Event(PLAYER_READY));
        }

        public function queueVideoById(videoID : String, quality : String = QUALITY_DEFAULT):void 
        {
            ytPlayer.cueVideoById(videoID, 0, quality);
        }

        public function loadVideoById(videoID : String, quality : String = QUALITY_DEFAULT):void 
        {
            ytPlayer.loadVideoById(videoID, 0, quality);
        }

        public function queueVideoByUrl(url : String, quality : String = QUALITY_DEFAULT):void 
        {
            ytPlayer.cueVideoByUrl(url, 0, quality);
        }

        public function loadVideoByUrl(url : String, quality : String = QUALITY_DEFAULT):void 
        {
            ytPlayer.loadVideoByUrl(url, 0, quality);
        }

        public function setSize(w:int, h:int):void 
        {
            ytPlayer.setSize(w, h);
        }

        private function handlePlayerError(e:Event):void 
        {

        }

        private function handlePlayerStageChange(e:Event):void 
        {

        }

        private function handlePlayerQualityChange(e:Event):void 
        {

        }

        private function handleRemovedFromStage(e:Event):void 
        {
            removeEventListener(Event.REMOVED_FROM_STAGE, handleRemovedFromStage);
            dispose();
        }

        public function dispose():void 
        {
            ytPlayer.destroy();
            if (ldr) {
                if (contains(ldr)) {
                    removeChild(ldr);
                }
                ldr = null;
            }
        }

        /**
         * parse out the Youtube Video ID from the video URL
         * @param   url
         * @return String
         */
        public static function getIdFromURL(url:String):String
        {
            var parts : Array = [];
            if (url.indexOf("watch?v=") != -1) {
                parts = url.split("watch?v=");
            } else if (url.indexOf("watch/v/") != -1) {
                parts = url.split("watch/v/");
            } else if (url.indexOf("youtu.be/") != -1) {
                parts = url.split("youtu.be/");
            }
            return String(parts[1]).split("/").join("");
        }

        /**
         * get the thumbnail of the video
         * @param String youtube Video ID
         * @return URLRequest
         */
        public static function getThumbnail(videoId : String):URLRequest
        {
            return new URLRequest("http://img.youtube.com/vi/" + videoId + "/0.jpg"); 
        }

    }

}

推荐答案

我觉得不可能,看看错误信息,你应该看到他们主要要处理 YouTube 没有更新他们的事实跨域策略文件,并且没有指定元策略.这是他们的政策文件:

I don't think it's possible , look at the error messages and you should see that they mainly have to deal with the fact that YouTube hasn't updated their crossdomain policy file and doesn't specify a meta policy. here's their policy file:

 <!-- http://www.youtube.com/crossdomain.xml --> 
 <!DOCTYPE cross-domain-policy 
  SYSTEM "http://www.macromedia.com/xml/dtds/cross-domain-policy.dtd"> 
 <cross-domain-policy> 
  <allow-access-from domain="*.youtube.com" /> 
  <allow-access-from domain="s.ytimg.com" /> 
 </cross-domain-policy> 

他们需要像这样添加一行:

They need to add a line like this:

 <site-control permitted-cross-domain-policies="all"/>

这篇关于使用 Youtube AS3 Player API 时如何避免安全错误的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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