Go:从 defer 中返回 [英] Go: returning from defer

问题描述

如果函数发生恐慌(在 Go 中)，我想从函数返回错误:

I want to return an error from a function if it panics (in Go):

func getReport(filename string) (rep report, err error) {
    rep.data = make(map[string]float64)

    defer func() {
        if r := recover(); r != nil {
            fmt.Println("Recovered in f", r)
            err, _ = r.(error)
            return nil, err
        }
    }()
    panic("Report format not recognized.")
    // rest of the getReport function, which can try to out-of-bound-access a slice
    ...
} 

我似乎误解了恐慌和推迟的概念.有谁能赐教吗?

I appear to have misunderstood the very concept of panic and defer. Can anybody enlighten me?

推荐答案

在延迟函数中，您可以更改返回的参数，但不能返回新的集合.因此，对您现有的内容进行简单的更改即可使其发挥作用.

In a deferred function you can alter the returned parameters, but you can't return a new set. So a simple change to what you have will make it work.

你写的还有另一个问题，即你对 string 感到恐慌，但在你的类型断言中期望 error.

There is another problem with what you wrote, namely that the you've paniced with a string but are expecting an error in your type assertion.

这是对这两者的修复(Play)

Here is a fix for both of those (Play)

defer func() {
    if r := recover(); r != nil {
        fmt.Println("Recovered in f", r)
        // find out exactly what the error was and set err
        switch x := r.(type) {
        case string:
            err = errors.New(x)
        case error:
            err = x
        default:
            err = errors.New("Unknown panic")
        }
        // invalidate rep
        rep = nil
        // return the modified err and rep
    }
}()

这篇关于Go:从 defer 中返回的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！