打字稿Sequelize:传入通用模型 [英] TypeScript & Sequelize: Pass in generic Model

问题描述

我有这个代码

import { Model, DataTypes, Sequelize } from "sequelize";

class User extends Model {
    public id!: number;
    public firstName!: string;
    public readonly createdAt!: Date;
    public readonly updatedAt!: Date;
}

function async InitAndDefineModel(model: Model): void {
    const sequelize = new Sequelize({
        dialect: "sqlite",
        storage: ":memory:",
    });
    model.init{
        firstName: {
            allowNull: false,
            type: DataTypes.STRING,
        },
    },
    {
        sequelize,
    });
    const tables = await sequelize.showAllSchemas({});
    console.log(tables);
}

InitAndDefineModel(User);

console.log 语句返回:

The console.log statement returns:

// [ { name: 'Users' } ]

所以我知道代码有效，但是 TypeScript 抱怨说:

So I know the code works, however, TypeScript complains that:

Property 'init' is a static member of type 'Model<any, any>'ts(2576)

在 model.init(...) 调用上.

我认为 TS 认为我正在传递一个模型对象目录.我想我需要告诉它它是一种模型，或者传入的对象是从它扩展而来的.如何告诉 TypeScript 参数 model: Model 是有效的?我尝试使用 model: Model<T> 和 `model: T 任何其他变体，但无济于事.

I think TS thinks I'm passing in a Model object directory. I guess I need to tell it it's a type of Model, or the object passed in was extended from it. How do I tell TypeScript that the argument model: Model is valid? I tried to use model: Model<T> and `model: T any other variations, but to no avail.

推荐答案

您应该为您的模型创建一个静态类型表示，例如:

You should create a static type representation of your models like:

type ModelStatic = typeof Model & {
  new(values?: object, options?: Sequelize.BuildOptions): Model;
}

您可以像这样定义 InitAndDefineModel 函数:

And you could define the InitAndDefineModel function like this:

function async InitAndDefineModel(model: ModelStatic): void

在这种情况下，传递给上述函数的 model 现在应该允许访问 Sequelize.Model

In such a case the model passed to above function should now allow to access static methods of Sequelize.Model

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