使用 Sequelize 查询自联接,包括相关记录 [英] Query self-join with Sequelize, including related record

查看:35
本文介绍了使用 Sequelize 查询自联接,包括相关记录的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我们将 Postgres 用于 Node.js 应用程序,并有一个 Sequelize 模型 Entry,大致定义为:

We're using Postgres for a Node.js app and have a Sequelize model Entry which is roughly defined as:

const entriesModel = sequelize.define('Entry',
    {
        id: {
            type: DataTypes.INTEGER,
            primaryKey: true,
            autoIncrement: true
        },
        post_date: {
            type: DataTypes.DATE,
            allowNull: false,
            defaultValue: () => new Date()
        }
        /* ...more fields here, etc, etc... */
    }, {
        classMethods: {
            associate: (models) => {
                entriesModel.hasOne(models.Entry, {
                    onDelete: 'CASCADE',
                    foreignKey: {
                        name: 'parent_id',
                        allowNull: true
                    },
                    as: 'ParentEntry'
                });
            }
        }
    }
);

基本上,一个条目可能有一个对应的父条目.我想检索所有条目并提取它们的父条目,但是当我尝试时:

Basically, an entry may have a corresponding parent entry. I want to retrieve all of the entries and pull through their parent entries, but when I try:

return models.Entry.findById(id, {
    include: [
        {
            model: models.Entry,
            where: {
                parent_id: id
            }
        }
    ]
})
.then(entry => Promise.resolve(cb(null, entry)))
.catch(error => Promise.resolve(cb(error)));

我收到错误:条目未与条目关联!"

I get the error: "Entry is not associated to Entry!"

如何进行此查询并从同一张表中的另一条记录中提取相关数据?

推荐答案

尝试使用您已经在关联中定义的名称传递 as 属性:

Try to pass as property with name that you already defined in the association:

return models.Entry.findById(id, {
    include: [{
        model: models.Entry,
        as: 'ParentEntry'
    }]
})

这篇关于使用 Sequelize 查询自联接,包括相关记录的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆