iOS UIWebView 应用在 Safari 中打开链接 [英] iOS UIWebView app opens link in Safari

问题描述

我有一个 iOS 应用程序，它只有一个视图，即 UIWebView(它打开应用程序的主要内容).我希望当我在某处(例如在表格行上)单击应用程序以在 Safari 浏览器中打开特定链接，而不是在 UIWebView 内.

I have an iOS app which has only one view and that is UIWebView (It opens the main content of the app). I would like when I make a click somewhere(e.g on a table row) the app to opens specific link in Safari browser not inside the UIWebView.

这是否可行，无需编写任何 iOS 代码，而是让 JavaScript 在 Safari 本身中打开该链接?

Is that doable without writing any iOS code and instead of that make the JavaScript opens that link in Safari itself ?

我有那个代码，但它根本没有帮助:

I have thatcode,but it doesn't help at all:

HTML 代码

<tr class='link-to-pdf' data-href='www.example.com'>

JS 代码:

 $(".link-to-pdf").click(function () {

            var a = document.createElement('a');
            a.setAttribute("href", this.getAttribute("data-href"));
            a.setAttribute("target", "_blank");

            var dispatch = document.createEvent("HTMLEvents");
            dispatch.initEvent("click", true, true);
            a.dispatchEvent(dispatch);

        });

推荐答案

在某些情况下，您可以告诉 javascript 中所有具有 target="_blank" 的链接，并将它们传递给 window.使用_system"参数打开.这适用于 iOS 和 Android.

In some cases, you can tell all links in your javascript that have target="_blank", and pass them to window.open with the '_system' param. This will work on both iOS and Android.

$(document).on('click', 'a[target="_blank"]', function(ev) {
  var url;

  ev.preventDefault();
  url = $(this).attr('href');
  window.open(url, '_system');
});

或者在您的情况下，只需将 a.setAttribute("target", "_blank"); 替换为 a.setAttribute("target", "_system");

Or in your case, simply replace a.setAttribute("target", "_blank"); with a.setAttribute("target", "_system");

这在一个古老的项目中对我有用，但我不确定它是否仍然有效(在 iOS 和 Android 上)

This worked for me in an ancient projekt, but im unsure if it still works (on iOS and Android)

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