来自 .ajax() 调用的数据的 jQuery .find() 正在返回“[object Object]".而不是 div [英] jQuery .find() on data from .ajax() call is returning "[object Object]" instead of div

问题描述

试图在 .ajax() 使用 .find().不幸的是，alert(result) 不返回 div#result.

这是我的代码:

$.ajax({网址:网址，缓存:假，成功:功能(响应){结果 = $(response).find("#result");警报(响应)；//按预期工作(返回所有 html)警报(结果)；//返回 [object 对象]}});

解决方案

具体回答您的问题，它似乎工作正常.您说它返回 [object Object]，这就是 jQuery 使用 find("#result") 方法返回的内容.它返回一个匹配 find 查询的 jQuery 元素.

尝试获取该对象的属性，例如 result.attr("id") - 它应该返回 result.

<小时>

一般来说，这个答案取决于 #result 是否是顶级元素.

如果#result是顶级元素，

<div id="结果"><span>文本</span></div><div id="其他顶级元素"></div>

find() 将不起作用.相反，使用 filter():

var $result = $(response).filter('#result');

如果#result不是顶级元素，

<div id="结果"><span>文本</span></div></div>

find() 会起作用:

var $result = $(response).find('#result');

Trying to find div element with id="result" in returned data from .ajax() using .find(). Unfortunately, alert(result) doesn't return div#result.

Here is my code:

$.ajax({
    url: url, 
    cache: false,
    success: function(response) {
        result = $(response).find("#result");
        alert(response); // works as expected (returns all html)
        alert(result); // returns [object Object]
    }
});

解决方案

To answer your question specifically, it seems to be working correctly. You said that it returns [object Object], which is what jQuery will return with the find("#result") method. It returns a jQuery element that matches the find query.

Try getting an attribute of that object, like result.attr("id") - it should return result.

---

In general, this answer depends on whether or not #result is the top level element.

If #result is the top level element,

<!-- #result as top level element -->
<div id="result">
  <span>Text</span>
</div>
<div id="other-top-level-element"></div>

find() will not work. Instead, use filter():

var $result = $(response).filter('#result');

If #result is not the top level element,

<!-- #result not as top level element -->
<div>
  <div id="result">
    <span>Text</span>
  </div>
</div>

find() will work:

var $result = $(response).find('#result');

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