如何将列表值复制到颤振中的另一个列表 [英] How to copy list values to another list in flutter
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问题描述
我正在尝试将一个列表的值复制到另一个,我使用三个按钮第一个将值附加到 mylist,第二个用于清除 mylist,第三个按钮将值从 mynewlist 复制到 mylist.
I am trying to copy values of one list to another, I use three buttons 1st one to append a value to mylist, second one to clear the mylist, 3rd button to copy values from mynewlist to mylist.
我试过了
List<String> mylist = [
'Albania',
'Andorra',
'Armenia',
'Austria',
'Azerbaijan',
'Belarus',
'Belgium',
'Albania',
'Andorra',
'Armenia',
'Austria',
'Azerbaijan',
'Belarus',
'Belgium',
];
List<String> mynewlist = [
'Albania',
'Andorra',
'Armenia',
'Austria',
'Azerbaijan',
'Belarus',
'Belgium',
'Albania',
'Andorra',
'Armenia',
'Austria',
'Azerbaijan',
'Belarus',
'Belgium',
];
Padding(
padding: const EdgeInsets.all(5.0),
child: Row(
children: <Widget>[
Expanded(
child: FlatButton(
onPressed: () {
setState(() {
print('clicked 1st');
print(mylist.length);
print(mynewlist.length);
mylist.add('sdsds');
});
},
child: Container(
child: Column(
children: <Widget>[
Image.asset(
'images/bulb.png',
width: 100,
height: 100,
),
Text('bulb')
],
),
),
),
),
Expanded(
child: FlatButton(
onPressed: () {
setState(() {
print('clicked 2nd');
print(mylist.length);
print(mynewlist.length);
//after i set mylist = mynewlist; when i click this button it clears the old and new list.
mylist.removeRange(0, mylist.length);
});
},
child: Container(
child: Column(
children: <Widget>[
Image.asset(
'images/bulb.png',
width: 100,
height: 100,
),
Text('bulb')
],
),
),
),
),
Expanded(
child: FlatButton(
onPressed: () {
setState(() {
print('clicked 3rd');
print(mylist.length);
print(mynewlist.length);
mylist = mynewlist;
});
},
child: Container(
child: Column(
children: <Widget>[
Image.asset(
'images/bulb.png',
width: 100,
height: 100,
),
Text('bulb')
],
),
),
),
),
],
),
)
在我第二次单击第二个按钮时它会完美运行,它会清除 mylist 和 mynewlist.
On the initial time it works perfectly the second time i click the second button it clears the mylist and mynewlist.
如何在不清除新列表的情况下复制第二个列表的值
How can i copy the values of second list without clearing the new new list
推荐答案
使用 myList = List.from(mynewlist);
代替 mylist = mynewlist;
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