使用 XSLT 减少 XML 输出 [英] use XSLT to pare down XML output

问题描述

如何使用 XSLT，从我的输入 xml 到我的输出 XML 中只选择一些 xml 标记?示例输入:

How can I using XSLT, select only some xml tags from my input xml to my output XML? example input:

<Country value="USA">
    <State value="KY>
        <City value="Hebron" />
        <City value="Lexington" />
        <City value="Owensboro" />
        <City value="Jonesville" />
    </State>
    <State value="OH">
         <City value="Cincinnati" />
         <City value="Columbus" />
         <City value="Cleveland" />
         <City value="Jonesville" />
    </State>
    <State value="IN" >
         <City value="Indianapolis" />
    </State>
 </Country>

那么，保留国家/州标签并仅复制希伯伦和辛辛那提?

So, keep the Country/State tags in place and only copy Hebron and Cincinnati?

预期输出:

<Country value="USA">
    <State value="KY>
        <City value="Hebron" />
    </State>
    <State value="OH">
         <City value="Cincinnati" />
    </State>
 </Country>

推荐答案

以下样式表:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()" />
        </xsl:copy>
    </xsl:template>
    <xsl:template match="City[not(@value='Hebron' or @value='Cincinnati')]" />
</xsl:stylesheet>

在这个输入上:

<Country value="USA">
    <State value="KY">
        <City value="Hebron" />
        <City value="Lexington" />
        <City value="Owensboro" />
    </State>
    <State value="OH">
        <City value="Cincinnati" />
        <City value="Columbus" />
        <City value="Cleveland" />
    </State>
</Country>

产生以下结果:

<Country value="USA">
    <State value="KY">
        <City value="Hebron" />
    </State>
    <State value="OH">
        <City value="Cincinnati" />
    </State>
</Country>

此样式表使用 身份转换 将除不需要的节点之外的所有节点原样复制到输出中.

This stylesheet uses the identity transform to copy all but the undesired nodes to the output unchanged.

另一个例子

您可能还想删除任何没有所需城市的 State 元素.这个样式表:

You might also want to remove any State element that does not have a desired city. This stylesheet:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="City[not(@value='Hebron' or @value='Cincinnati')]"/>
    <xsl:template 
           match="State[not(City[@value='Hebron' or @value='Cincinnati'])]"/>
</xsl:stylesheet>

应用于此输入:

<Country value="USA">
    <State value="KY">
        <City value="Hebron" />
        <City value="Lexington" />
        <City value="Owensboro" />
    </State>
    <State value="OH">
        <City value="Cincinnati" />
        <City value="Columbus" />
        <City value="Cleveland" />
    </State>
    <State value="MO">
        <City value="St. Louis" />
    </State>
</Country>

生产:

<Country value="USA">
    <State value="KY">
        <City value="Hebron" />
    </State>
    <State value="OH">
        <City value="Cincinnati" />
    </State>
</Country>

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