如何在条件下使用 bash 返回码? [英] How to use bash return code in conditional?
问题描述
我有一小段代码可以检查 IP 地址的有效性:
I have a small piece of code which checks IP address validity :
function valid_ip()
{
local ip=$1
local stat=1
if [[ $ip =~ ^[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}$ ]]; then
OIFS=$IFS
IFS='.'
ip=($ip)
IFS=$OIFS
if [[ ${ip[0]} -le 255 && ${ip[1]} -le 255
&& ${ip[2]} -le 255 && ${ip[3]} -le 255 ]]; then
stat=1
else
stat=0
fi
fi
return $stat
}
但我在 bash 条件句中使用它时遇到问题.我尝试了许多技术来测试它的返回值,但大多数都失败了.
But I am having problems with its usage in bash conditionals. I have tried many techniques to test its return value but most of them fail on me.
if [[ !$(valid_ip $IP) ]]; then
if [[ $(valid_ip IP) -eq 1 ]]; then
等等.等任何人都可以建议我应该在这里做什么?
etc. etc. Can anyone suggest what should I do here ?
编辑
根据您的建议,我使用了类似的东西:
Following your suggestions I have used something like :
if valid_ip "$IP" ; then
... do stuff
else
perr "IP: "$IP" is not a valid IP address"
fi
我收到类似
IP:10.9.205.228"不是有效的 IP 地址
IP: "10.9.205.228" is not a valid IP address
推荐答案
返回码在命令退出后的特殊参数$?
中可用.通常,您只需要在运行另一个命令之前保存它的值时使用它:
The return code is available in the special parameter $?
after the command exits. Typically, you only need to use it when you want to save its value before running another command:
valid_ip "$IP1"
status1=$?
valid_ip "$IP2"
if [ $status1 -eq 0 ] || [ $? -eq 0 ]; then
或者如果你需要区分各种非零状态:
or if you need to distinguish between various non-zero statuses:
valid_ip "$IP"
case $? in
1) echo valid_IP failed because of foo ;;
2) echo valid_IP failed because of bar ;;
0) echo Success ;;
esac
否则,您让各种运算符隐式检查:
Otherwise, you let the various operators check it implicitly:
if valid_ip "$IP"; then
echo "OK"
fi
valid_IP "$IP" && echo "OK"
<小时>
这是一个简单、惯用的 valid_ip
编写方式:
valid_ip () {
local ip=$1
[[ $ip =~ ^[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}$ ]] && {
IFS='.' read a b c d <<< "$ip"
(( a < 255 && b < 255 && c < 255 && d << 255 ))
}
}
有两个表达式,[[...]]
和 { ... }
;两者由 &&
连接.如果第一个失败,则 valid_ip
失败.如果成功,则计算第二个表达式(复合语句).read
将字符串拆分为四个变量,每个变量在算术表达式中分别进行测试.如果都为真,则((...))
成功,即&&
列表成功,即valid_ip
成功.无需存储或返回显式返回码.
There are two expressions, the [[...]]
and the { ... }
; the two are joined by &&
. If the first fails, then valid_ip
fails. If it suceeds, then the second expression (the compound statement) is evaluated. The read
splits the string into four variables, and each is tested separately inside the arithmetic expression. If all are true, then the ((...))
succeeds, which means the &&
list succeeds, which means that valid_ip
succeeds. No need to store or return explicit return codes.
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