基于另一个数据集获取数据集的子集 [英] take subset of dataset based on another dataset

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本文介绍了基于另一个数据集获取数据集的子集的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

假设我有一个数据集,即 dat1

suppose I have one dataset, which is dat1

ID  block   plot    SPID    TotHeight
1   1   1   4   44.5
2   1   1   4   51
3   1   1   4   28.7
4   1   1   4   24.5
5   1   1   4   27.3
6   1   1   4   20
17  1   10  1   44.5
19  1   10  1   51
1   1   11  21  28.7
2   1   11  21  24.5
3   1   11  21  27.3
4   1   11  21  20
5   1   11  21  12.88666667
6   1   11  21  7.235238095
7   1   11  21  1.583809524

然后我还有一个大数据集,就是dat2:

Then I have another big dataset, which is dat2:

ID  block   plot    SPID    Species TotHeight
1   1   1   4   BENI    72
2   1   1   4   BENI    55
3   1   1   4   BENI    51
4   1   1   4   BENI    47
5   1   1   4   BENI    49
6   1   1   4   BENI    34
7   1   1   4   BENI    .
8   1   1   4   BENI    51
9   1   1   4   BENI    66
10  1   1   4   BENI    40
11  1   1   4   BENI    24
12  1   1   4   BENI    62
13  1   1   4   BENI    34
14  1   1   4   BENI    49
15  1   1   4   BENI    57
16  1   1   4   BENI    22
17  1   1   4   BENI    76
18  1   1   4   BENI    56
19  1   1   4   BENI    55
20  1   1   4   BENI    29
21  1   1   4   BENI    24
22  1   1   4   BENI    18
23  1   1   4   BENI    65
24  1   1   4   BENI    55
25  1   1   4   BENI    63
26  1   1   4   BENI    57
27  1   1   4   BENI    57
28  1   1   4   BENI    57
29  1   1   4   BENI    45
30  1   1   4   BENI    83
31  1   1   4   BENI    37
32  1   1   4   BENI    56
33  1   1   4   BENI    65
34  1   1   4   BENI    75
35  1   1   4   BENI    51
36  1   1   4   BENI    .
1   1   2   16  PRSE    141
2   1   2   16  PRSE    192
3   1   2   16  PRSE    .
4   1   2   16  PRSE    197
5   1   2   16  PRSE    172
6   1   2   16  PRSE    143
7   1   2   16  PRSE    141
8   1   2   16  PRSE    155
9   1   2   16  PRSE    167
10  1   2   16  PRSE    155
11  1   2   16  PRSE    175
12  1   2   16  PRSE    190
13  1   2   16  PRSE    148
14  1   2   16  PRSE    180
15  1   2   16  PRSE    .

我的问题是如何从 dat2 中获取 ID、块和绘图与 dat1 中的数据匹配的数据子集?以及如何从 dat2 中获取 ID、block 和 plot 与 dat1 中的不匹配的数据子集?

My question is how can I take a subset of data from dat2 in which ID, block and plot match those in dat1? And how can I get a subset of data from dat2 in which ID, block and plot do not match those in dat1?

推荐答案

听起来你想要对列 ID、块和绘图进行 merge.

It sounds like you want a merge on the columns ID, block, and plot.

假设您的数据是在名为 dat1dat2 中读取的,这应该是您想要的:

Assuming your data are read in named dat1 and dat2, this should be what you want:

> merge(dat1, dat2, by = c("ID", "block", "plot"))
  ID block plot SPID.x TotHeight.x SPID.y Species TotHeight.y
1  1     1    1      4        44.5      4    BENI          72
2  2     1    1      4        51.0      4    BENI          55
3  3     1    1      4        28.7      4    BENI          51
4  4     1    1      4        24.5      4    BENI          47
5  5     1    1      4        27.3      4    BENI          49
6  6     1    1      4        20.0      4    BENI          34

这实质上是对感兴趣的三列执行 SQL 术语内连接.如果您也感兴趣,请阅读有关左、右和外连接可能性的合并帮助页面.

This essentially performs an inner join in SQL terms on the three columns of interest. Read the help page for merge for left, right, and outer join possibilities if that is also of interest.

完全可重现的要点这里

要从 dat2 获取未合并的行,此 hack 有效.可能有一种更有效的方法可以做到这一点,但就是这样.首先,添加参数all.y = TRUE.这指定了一个右连接,它将从 dat2 返回未合并的行.然后我们可以知道没有合并的行将返回 NA's:

To get the rows that didn't merge from dat2, this hack works. There is probably a more efficient way to do this, but here it is. First, add the parameter all.y = TRUE. This specifies a right join which will return rows from dat2 which did not merge. Then we can subset on that knowing that the rows that didn't merge will return NA's:

subset(merge(dat1, dat2, by = c("ID", "block", "plot"), all.y = TRUE), is.na(SPID.x) == TRUE)

这篇关于基于另一个数据集获取数据集的子集的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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