创建您的控制器或视图模型一个DropDownList [英] Creating a dropdownlist from your controller or view model

问题描述

我怎么会在我的控制器创建的SelectList并把它传递给我的看法？我需要给 - 选择 - 选项的值为0

How would I create a SelectList in my controller and pass it to my view? I need to give the "-- Select --" option a value of 0.

我回应回答说，我是从流利验证的Jeremey了

I'm responding to the replies that I got from Jeremey of Fluent Validation.

这是我目前有。我的视图模型：

This is what I currently have. My view model:

[Validator(typeof(CreateCategoryViewModelValidator))]
public class CreateCategoryViewModel
{
    public CreateCategoryViewModel()
    {
        IsActive = true;
    }

    public string Name { get; set; }
    public string Description { get; set; }
    public string MetaKeywords { get; set; }
    public string MetaDescription { get; set; }
    public bool IsActive { get; set; }
    public IList<Category> ParentCategories { get; set; }
    public int ParentCategoryId { get; set; }
}

我的控制器。

public ActionResult Create()
{
    List<Category> parentCategoriesList = categoryService.GetParentCategories();

    CreateCategoryViewModel createCategoryViewModel = new CreateCategoryViewModel
    {
        ParentCategories = parentCategoriesList
    };

    return View(createCategoryViewModel);
}

这是我在我的观点：

@Html.DropDownListFor(x => x.ParentCategoryId, new SelectList(Model.ParentCategories, "Id", "Name", Model.ParentCategoryId), "-- Select --")

如何创建在控制器或视图模型一个下拉列表，并把它传递给看法？我需要 - 选择 - 选项，值为0

How do I create a dropdown list in the controller or view model and pass it to the view? I need the "-- Select --" option to have a value of 0.

推荐答案

在你的模型中，将的IList＆LT;类别＆GT; 到的SelectList ，然后实例像这样...

In your model, change the IList<Category> to SelectList and then instantiate it like this...

List<ParentCategory> parentCategories = categoryService.GetParentCategories();

parentCategories.Insert(0, new ParentCategory(){ Id = "0", Name = "--Select--"});

ParentCategories = new SelectList(parentCategories, "Id", "Name");

然后在你的观点，你可以简单地调用

Then in your view you can simply call

@Html.DropDownListFor(m => m.ParentCategoryId, Model.ParentCategories);

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