Python:矩形参数无效 [英] Python: rect argument is invalid

问题描述

您好，我正在尝试学习 python，但我遇到了这个问题，当我运行我的程序时，它说 rect 参数无效，这是我的代码:

import pygamepygame.init()win = pygame.display.set_mode((500,500))pygame.display.set_caption("第一场比赛")x = 50y = 50宽度 = 40高度 = 60维尔 = 5运行=真运行时:pygame.time.delay(100)对于 pygame.event.get() 中的事件:如果 event.type == pygame.QUIT:运行 = 假pygame.draw.rect(win, (255, 0, 0),(x, y, width, height, vel))pygame.display.update()pygame.quit()

错误:

<块引用>

Traceback(最近一次调用最后一次):文件..."，第 25 行，在 <module>pygame.draw.rect(win, (255, 0, 0),(x, y, width, height, vel))TypeError: Rect 参数无效

解决方案

pygame.draw.rect 必须是一个包含 4 个元素的元组:

pygame.draw.rect(win, (255, 0, 0),(x, y, width, height, vel))

pygame.draw.rect(win, (255, 0, 0),(x, y, width, height))

或者，它可以是 pygame.Rect 对象:

rect = pygame.Rect(x, y, width, height)pygame.draw.rect(win, (255, 0, 0), 矩形)

Hi I'm trying to learn python and but i'm stuck with this problem, when i run my program it says rect argument is invalid, this is my code:

import pygame
pygame.init()

win = pygame.display.set_mode((500,500))

pygame.display.set_caption("First game")

x = 50
y = 50
width = 40
height = 60
vel = 5

run = True
while run:
    pygame.time.delay(100)

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    pygame.draw.rect(win, (255, 0, 0),(x, y, width, height, vel))
    pygame.display.update()

pygame.quit()

Error:

Traceback (most recent call last):
 File "...", line 25, in <module>
   pygame.draw.rect(win, (255, 0, 0),(x, y, width, height, vel))
TypeError: Rect argument is invalid

解决方案

The 3rd argument of pygame.draw.rect has to be a tuple with 4 elements:

pygame.draw.rect(win, (255, 0, 0),(x, y, width, height, vel))

pygame.draw.rect(win, (255, 0, 0),(x, y, width, height))

Alternatively it can be a pygame.Rect object, too:

rect = pygame.Rect(x, y, width, height)
pygame.draw.rect(win, (255, 0, 0), rect)

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