在bash中，如何将N个参数连接在一起作为空格分隔的字符串 [英] In bash, how do I join N parameters together as a space separated string

问题描述

I'm trying to write a function that takes n parameters and joins them into a string.

In Perl it would be

my $string = join(' ', @ARGV);

but in bash I don't know how to do it

function()
{
    ??
}

解决方案

Check the bash man page for the entry for '*' under Special Parameters.

join () {
    echo "$*"
}

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