打印 Python 函数中键入的参数名称 [英] Print name of argument typed in functions in Python

问题描述

我有类似的东西

def myfunc(list):

当我调用函数时，我可以输入类似

When I call the function, I can type like

myfunc(List1)

有没有办法打印出函数中作为参数输入的列表?比如:

There is a way to print out the list typed as argument in the function? Something like:

def myfunc(list):
    print (list.name)

那会给出:

myfunc(List1)
List1

提前谢谢你

推荐答案

一个变体 建议by omri-saadon，是使用 inspect.getframeinfo 其中列出了code_context.

A variant over the one suggested by omri-saadon, is to use inspect.getframeinfo which lists the code_context.

import inspect

def debug(*args):

    try:  # find code_context

        # First try to use currentframe() (maybe not available all implementations)
        frame = inspect.currentframe()
        if frame:
            # Found a frame, so get the info, and strip space from the code_context
            code_context = inspect.getframeinfo(frame.f_back).code_context[0].strip()
        else:

            # No frame, so use stack one level above us, and strip space around
            # the 4th element, code_context
            code_context = inspect.stack()[1][4][0].strip()

    finally:
         # Deterministic free references to the frame, to be on the safe side
         del frame

    print('Code context: {}'.format(code_context))
    print('Actual arguments: {}'.format(args))


## Test code to have something to output #########
def my_seventh():
   return 7

a = 0.2
b = 1.2
c = a + 1
my_eight = my_seventh

debug(a, b, c, b+2)
debug([4.1, 4.2], (5.1, 5.2), {6.1: 6.2}, my_seventh, my_eight, my_eight())

my_list = [1, 2, 3, 4, 5]

def first_level():
    def second_level():
         debug(my_list[:2],
               my_list[3:])

    second_level()

first_level()

运行这段代码时的输出是:

Output when running this code is:

Code context: debug(a, b, c, b+2)
Actual arguments: (0.2, 1.2, 1.2, 3.2)
Code context: debug([4.1, 4.2], (5.1, 5.2), {6.1: 6.2}, my_seventh, my_eight, my_eight())
Actual arguments: ([4.1, 4.2], (5.1, 5.2), {6.1: 6.2}, <function my_seventh at 0x102294488>, <function my_seventh at 0x102294488>, 7)
Code context: my_list[3:])
Actual arguments: ([1, 2], [4, 5])

换句话说，使用检查选项获取 frameinfo 将为您提供触发函数调用的源代码行(或最后一行).但是，如果实际调用被拆分为多行，则只有最后一行作为代码上下文给出.到目前为止，我还没有找到将代码上下文中的命名变量连接到实际参数的方法.

In other words, using the inspect options to get the frameinfo will give you the source line (or last line thereof) which triggered your function call. However if the actual call is split over multiple lines, only the last line is given as code context. And so far I've not found a way to connect the named variables in the code context to the actual arguments.

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