在 Python 中获取精确的 Android GPS 位置 [英] Get precise Android GPS-Location in Python

问题描述

我尝试在 Python 中获取我的 Android 手机的 GPS 位置(使用 QPython3 应用程序).这种工作，但似乎Android中有几个LocationProviders:

I try to obtain the GPS-Location of my Android Phone in Python (using QPython3 app). This kind of works, but it seems there are several LocationProviders in Android:

• gps:纯gps定位，速度慢，耗能，但非常准确，正是我需要的.
• 网络:混合使用 gps 和 wifi/蜂窝定位，速度更快，但准确度较低
• 被动:与上面类似，但完全不使用 GPS

• gps: pure gps location, slow, energy consuming, but very accurate, and exactly what I need.
• network: mix of gps and wifi/cell locating, faster, but less accurate
• passive: like above but completely without using gps

问题:当我运行我的脚本(如下)时，我只能得到网络"提供的位置这还不够准确.

Problem: When I run my script (below) I only get my location provided by "network" wich is not accurate enough.

但我找不到强制使用特定 LocationProvider 的方法.

But I can't find a way to force a specific LocationProvider.

代码:

# import needed modules
import android
import time
import sys, select, os #for loop exit

#Initiate android-module
droid = android.Android()

#notify me
droid.makeToast("fetching GPS data")

print("start gps-sensor...")
droid.startLocating()

while True:
    #exit loop hook
    if sys.stdin in select.select([sys.stdin], [], [], 0)[0]:
        line = input()
        print("exit endless loop...")
        break

    #wait for location-event
    event = droid.eventWaitFor('location',10000).result
    if event['name'] == "location":
        try:
            #try to get gps location data
            timestamp = repr(event['data']['gps']['time'])
            longitude = repr(event['data']['gps']['longitude'])
            latitude = repr(event['data']['gps']['latitude'])
            altitude = repr(event['data']['gps']['altitude'])
            speed = repr(event['data']['gps']['speed'])
            accuracy = repr(event['data']['gps']['accuracy'])
            loctype = "gps"
        except KeyError:
            #if no gps data, get the network location instead (inaccurate)
            timestamp = repr(event['data']['network']['time'])
            longitude = repr(event['data']['network']['longitude'])
            latitude = repr(event['data']['network']['latitude'])
            altitude = repr(event['data']['network']['altitude'])
            speed = repr(event['data']['network']['speed'])
            accuracy = repr(event['data']['network']['accuracy'])
            loctype = "net"

        data = loctype + ";" + timestamp + ";" + longitude + ";" + latitude + ";" + altitude + ";" + speed + ";" + accuracy

    print(data) #logging
    time.sleep(5) #wait for 5 seconds

print("stop gps-sensor...")
droid.stopLocating()

样本输出(假坐标):

net;1429704519675;37.235065;-115.811117;0;0;23
net;1429704519675;37.235065;-115.811117;0;0;23
net;1429704519675;37.235065;-115.811117;0;0;23

总结:如何使用 Python 在 Android 中获取精确的 GPS 位置?

Summarization: How do I get a precise GPS location in Android using Python?

提前谢谢大家！

已测试:

• 里面/外面
• 启用/禁用
• 启用 WiFi GPS(在运行脚本之前)

推荐答案

droid = android.Android()
droid.startLocating(0, 0)
event = droid.eventWait(1000).result
if event['name'] == "location":
  print(event['data']['gps'])
droid.stopLocating()

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