Guzzle - Laravel.如何使用 x-www-form-url-encoded 发出请求 [英] Guzzle - Laravel. How to make request with x-www-form-url-encoded

问题描述

我需要集成一个 API，所以我编写了函数:

I need to integrate an API so I write function:

public function test() {

    $client = new GuzzleHttpClient();

try {
    $res = $client->post('http://example.co.uk/auth/token', [

    'headers' => [
        'Content-Type' => 'application/x-www-form-urlencoded',
            ],

    'json' => [
        'cliend_id' => 'SOMEID',
        'client_secret' => '9999jjjj67Y0LBLq8CbftgfdreehYEI=',
        'grant_type' => 'client_credentials'
]
            ]);

$res = json_decode($res->getBody()->getContents(), true);
dd($res);

}
catch (GuzzleHttpExceptionClientException $e) {
        $response = $e->getResponse();
        $result =  json_decode($response->getBody()->getContents());

    return response()->json(['data' => $result]);

    }

}

作为回复，我收到了消息:

as a responde I got message:

{"data":{"error":"invalid_clientId","error_description":"ClientId should be sent."}}

现在，当我尝试在 POSTMAN 应用程序中使用相同的数据运行相同的 url 时，我会得到正确的结果:

Now when I try to run the same url with same data in POSTMAN app then I get correct results:

我的代码有什么不好的地方?我发送了正确的 form_params 我也尝试将 form_params 更改为 json 但我又遇到了同样的错误......

What is bad in my code? I send correct form_params also I try to change form_params to json but again I got the same error...

如何解决我的问题?

推荐答案

问题是在 Postman 中你是以表单形式发送数据，但在 Guzzle 中你是在 'json' 中传递数据 选项数组的键.

The problem is that in Postman you're sending the data as a form, but in Guzzle you're passing the data in the 'json' key of the options array.

我敢打赌，如果你将 'json' 切换为 'form_params'，你会得到你想要的结果.

I bet that if you would switch the 'json' to 'form_params' you would get the result you're looking for.

$res = $client->post('http://example.co.uk/auth/token', [
    'form_params' => [
        'client_id' => 'SOMEID',
        'client_secret' => '9999jjjj67Y0LBLq8CbftgfdreehYEI=',
        'grant_type' => 'client_credentials'
    ]
]);

这里是相关文档的链接:http://docs.guzzlephp.org/en/stable/quickstart.html#sending-form-fields

Here's a link to the docs in question: http://docs.guzzlephp.org/en/stable/quickstart.html#sending-form-fields

另外，我注意到一个错字 - 你有 cliend_id 而不是 client_id.

Also, I noticed a typo - you have cliend_id instead of client_id.

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