Java 1.4 同步:只允许一个方法实例运行(非阻塞)? [英] Java 1.4 synchronization: only allow one instance of method to run (non blocking)?

问题描述

我有一堂课建议翻译实用程序.翻译本身应每 30 分钟重新加载一次.我为此使用 Spring Timer 支持.基本上，我的课看起来像:

I have a class proposing translations utilities. The translations themselves should be reloaded every 30 minutes. I use Spring Timer support for that. Basically, my class looks like :

public interface Translator {
    public void loadTranslations();
    public String getTranslation(String key);
}

loadTranslations() 运行时间可能很长，因此在运行时旧的翻译仍然可用.这是通过在本地地图中加载翻译并在加载所有翻译时更改参考来完成的.

loadTranslations() can be pretty long to run, so while it is running the old translations are still available. This is done by loading the translations in a local Map and just changing the reference when all translations are loaded.

我的问题是:我如何确保当一个线程已经在加载翻译时，第二个线程也尝试运行，它检测到并立即返回，而不开始第二次更新.

My problem is : how do I make sure that when a thread is already loading translations, is a second one also tries to run, it detects that and returns immediately, without starting a second update.

同步方法只会将负载排队...我仍在使用 Java 1.4，所以没有 java.util.concurrent.

A synchronized method will only queue the loads ... I'm still on Java 1.4, so no java.util.concurrent.

感谢您的帮助！

推荐答案

使用某种形式的锁定机制，仅在任务尚未进行时才执行.获取锁定令牌必须是一个一步的过程.见:

Use some form of locking mechanism to only perform the task if it is not already in progress. Acquiring the locking token must be a one-step process. See:

/**
 * @author McDowell
 */
public abstract class NonconcurrentTask implements Runnable {

    private boolean token = true;

    private synchronized boolean acquire() {
        boolean ret = token;
        token = false;
        return ret;
    }

    private synchronized void release() {
        token = true;
    }

    public final void run() {
        if (acquire()) {
            try {
                doTask();
            } finally {
                release();
            }
        }
    }

    protected abstract void doTask();

}

如果任务同时运行会抛出异常的测试代码:

Test code that will throw an exception if the task runs concurrently:

public class Test {

    public static void main(String[] args) {
        final NonconcurrentTask shared = new NonconcurrentTask() {
            private boolean working = false;

            protected void doTask() {
                System.out.println("Working: "
                        + Thread.currentThread().getName());
                if (working) {
                    throw new IllegalStateException();
                }
                working = true;
                try {
                    Thread.sleep(1000);
                } catch (InterruptedException e) {
                    throw new RuntimeException(e);
                }
                if (!working) {
                    throw new IllegalStateException();
                }
                working = false;
            }
        };

        Runnable taskWrapper = new Runnable() {
            public void run() {
                while (true) {
                    try {
                        Thread.sleep(100);
                    } catch (InterruptedException e) {
                        throw new RuntimeException(e);
                    }
                    shared.run();
                }
            }
        };
        for (int i = 0; i < 100; i++) {
            new Thread(taskWrapper).start();
        }
    }

}

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