如何在 SQL PIVOT 中排序 [英] How to ORDER BY in SQL PIVOT

问题描述

我目前有这个查询使用 PIVOT 生成这样的表:

I currently have this query using PIVOT generating a table like this:

  USER  |  DEC  |  NOV  |  OCT
---------------------------------
  bob   |   3   |   5   |   2
  jon   |   7   |   0   |   1 
  tim   |   4   |   2   |   6

我想做但看起来有点牵强的是，ORDER BY 按 DEC 值降序排列结果.

What I would like to do but it looks like a stretch is to ORDER BY the results by the DEC value descending.

这是查询:

with Mth (st, nd) as ( 
  select DATEADD (M, datediff (m, 0,'2012-09-01'), 0), 
         DATEADD (M, DATEDIFF (m, 0, '2012-09-01') + 1, 0)   
  union all 
  select DATEADD (m, 1, st), 
         DATEADD (m, 1, nd) 
  from Mth 
  where nd <= DATEADD (m, datediff (m, 0, getdate()), 0)
) 
select * 
from 
( 
  select MONTH(Mth.st) Month, 
      U.USER, 
      COUNT(S.QRY_ID) Searches 
  FROM Mth 
  LEFT JOIN SEARCHES S 
    on Mth.st <= S.CREATED 
    and Mth.nd > S.CREATED 
  LEFT JOIN MEMBERS U 
    on U.AID = S.AID 
  GROUP BY YEAR(Mth.st), MONTH(Mth.st), U.HOLDER_LOGIN
) src 
pivot 
( 
  sum(searches) 
  for month in ([12],[11],[10]) 
) piv

执行 piv ORDER BY piv.Searches 会报错，所以可以指定列吗?

Doing piv ORDER BY piv.Searches gives an error so is it possible to specify the column?

推荐答案

试试这个:

with Mth (st, nd) as ( 
  select DATEADD (M, datediff (m, 0,'2012-09-01'), 0), 
         DATEADD (M, DATEDIFF (m, 0, '2012-09-01') + 1, 0)   
  union all 
  select DATEADD (m, 1, st), 
         DATEADD (m, 1, nd) 
  from Mth 
  where nd <= DATEADD (m, datediff (m, 0, getdate()), 0)
), Pivoted
AS
(     
    select * 
    from 
    ( 
      select MONTH(Mth.st) Month, 
          U.USER, 
          COUNT(S.QRY_ID) Searches 
      FROM Mth 
      LEFT JOIN SEARCHES S 
        on Mth.st <= S.CREATED 
        and Mth.nd > S.CREATED 
      LEFT JOIN MEMBERS U 
        on U.AID = S.AID 
      GROUP BY YEAR(Mth.st), MONTH(Mth.st), U.HOLDER_LOGIN
    ) src 
    pivot 
    ( 
      sum(searches) 
      for month in ([12],[11],[10]) 
    ) piv
)
SELECT * 
FROM Pivoted
ORDER BY Dec

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