回复线程 google-api-ruby-client [英] reply to thread google-api-ruby-client

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问题描述

这就是我的代码(几乎)使用 google-api-ruby-client 创建消息的样子:

So here's what my code (pretty much) looks like to create a message using the google-api-ruby-client:

  service ||= Google::Apis::GmailV1::GmailService.new

  message = RMail::Message.new
  message.header['To'] = params[:gmail][:to]
  message.header['From'] = current_user_google_user_id
  message.header['Subject'] = params[:gmail][:subject]
  message.header['Subject'] = params[:gmail][:subject]
  message.body = params[:gmail][:body]

  service.send_user_message(
    current_user_google_user_id,
    upload_source: StringIO.new(message.to_s),
    content_type: 'message/rfc822',
    thread_id: params[:gmail][:thread_id]
  )

它显然失败了,因为我有 thread_id.如果我删除那条线,一切正常,但我无法将事情限制在一个线程中.我应该如何将线程 ID 传递给 GmailService?

It obviously fails because of where I have thread_id. If I remove that line, things work fine, but I'm not able to keep things scoped to a thread. How should I be passing the thread ID to the GmailService?

推荐答案

在 GitHub 上查看源代码 send_user_message 表明它不需要 thread_id作为参数.但是 Message 确实有它作为属性.

Looking at the source on GitHub for send_user_message shows that it doesn't take a thread_id as a parameter. However the Message class does have it as an attribute.

所以也许尝试这个应该可行:

So perhaps trying this should work:

  service ||= Google::Apis::GmailV1::GmailService.new

  message = RMail::Message.new
  message.header['To'] = params[:gmail][:to]
  message.header['From'] = current_user_google_user_id
  message.header['Subject'] = params[:gmail][:subject]
  message.header['Subject'] = params[:gmail][:subject]
  message.body = params[:gmail][:body]
  message.thread_id = params[:gmail][:thread_id]

  service.send_user_message(
    current_user_google_user_id,
    upload_source: StringIO.new(message.to_s),
    content_type: 'message/rfc822'
  )

这篇关于回复线程 google-api-ruby-client的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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