在 xtable 中处理 Latex 反斜杠 [英] Handling Latex backslashes in xtable

问题描述

我有一个包含以下列的表格:

I have a table that includes the following column:

 mytable <- data.frame(beta_0 = c(1,2,3)

我想要做的是在乳胶标记中输出一个带有列标题的表格，例如$eta_0$

What I want to do is output a table with a column header in latex markup, e.g. $eta_0$

但是，我似乎不知道如何使用 print.xtable 输出$eta_0$":

However, I can not seem to figure out how to output the "$eta_0$" using print.xtable:

colnames(mytable) <- "$eta_0$"
library(xtable)
print(xtable(mytable), include.rownames = F)

返回一个列标题

eta\_0$

而不是

$eta_0$

我认为答案是 print.xtable 的sanitize.colnames.function"参数，但我不清楚如何使用它，以及 ?print.xtable 没有提供示例.

I presume that the answer is the "sanitize.colnames.function" argument to print.xtable, but it is not obvious to me how to use this, and ?print.xtable provides no examples.

具体来说，我想输出一个像这样的乳胶表:

Specifically, I would like to output a latex table like:

egin{table}[ht]
 egin{center}
  egin{tabular}{r}
    hline
    $eta_0$ \ 
    hline
    1.00 \ 
    2.00 \ 
    3.00 \ 
    hline
  end{tabular}
 end{center}
end{table}

推荐答案

这里有两个问题；首先，您需要一个双反斜杠，否则它会将其视为控制序列.其次，默认情况下，xtable 会清理文本，使其不会破坏 LaTeX.使用 sanitize. 参数之一来控制它；要不进行消毒，请将其传递给身份函数.

Two issues here; first, you need a double backslash as otherwise it treats it as a control sequence. Second, by default, xtable sanitizes text so that it won't break LaTeX. Use one of the sanitize. parameters to control this; to do no sanitizing, pass it the identity function.

colnames(mytable) <- "$\beta_0$"
print(xtable(mytable), include.rownames = F, sanitize.colnames.function = identity)

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