在 WPF 中加载 BitmapSource 并使用相同的名称保存 ->IO异常 [英] Load a BitmapSource and save using the same name in WPF -> IOException

问题描述

当我尝试保存之前加载的 BitmapSource 时，抛出 System.IO.IOException 说明另一个进程正在访问该文件并且无法打开文件流.

When I try to save a BitmapSource that I loaded earlier, a System.IO.IOException is thrown stating another process is accessing that file and the filestream cannot be opened.

如果我只保存而不提前加载，一切正常.

If I only save whithout loading earlier, everything works fine.

加载代码:

BitmapImage image = new BitmapImage();

image.BeginInit();
image.UriSource = uri;

if (decodePixelWidth > 0)
image.DecodePixelWidth = decodePixelWidth;

image.EndInit();

保存代码:

using (FileStream fileStream = new FileStream(Directory + "\" + FileName + ".jpg", FileMode.Create))
{
    JpegBitmapEncoder encoder = new JpegBitmapEncoder();
    encoder.Frames.Add(BitmapFrame.Create((BitmapImage)image));
    encoder.QualityLevel = 100;
    encoder.Save(fileStream);
}

加载图像数据后，文件似乎仍然被锁定，并且在打开它的应用程序仍在运行时永远无法覆盖.任何想法如何解决这个问题?非常感谢任何解决方案.

It seems like after loading the image data, the file is still locked an can never be overwritten while the application who opened it is still running. Any ideas how to solve this? Thanks alot for any solutions.

推荐答案

受我对这个问题的评论的启发，我通过将所有字节读入内存流并将其用作 BitmapImage 的 Sreamsource 来解决问题.

Inspired by the comments I got on this issue, I solved the problem by reading all bytes into a memorystream and using it as the BitmapImage's Sreamsource.

这个效果很好:

if (File.Exists(filePath))
{
    MemoryStream memoryStream = new MemoryStream();

    byte[] fileBytes = File.ReadAllBytes(filePath);
    memoryStream.Write(fileBytes, 0, fileBytes.Length);
    memoryStream.Position = 0;

    image.BeginInit();
    image.StreamSource = memoryStream;

    if (decodePixelWidth > 0)
        image.DecodePixelWidth = decodePixelWidth;

    image.EndInit();
}

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