通过避免 django 模型保存方法中的完整性错误来增加 slug [英] Incrementing the slug by avoiding Integrity error in django models save method

问题描述

我有一个包含两个字段的模型，如下所示

I have a model with two fields as below

models.py

class Publisher(models.Model):
    name = models.CharField(max_length=200)
    slug = models.SlugField(max_length=150, unique=True)    

    def save(self, *args, **kwargs):
        if not self.id and not self.slug:
            slug = slugify(self.name)
            try:
                slug_exits = Publisher.objects.get(slug=slug)
                if slug_exits:
                    self.slug = slug + '_1'
            except Publisher.DoesNotExist:
                self.slug = slug
        super(Publisher, self).save(*args, **kwargs)

这里我正在创建一个基于 name 字段的 slug，正如我们在上面看到的那样

Here i am creating a slug based on the name field as we can see above

所以当我们尝试用name已经存在创建发布者时，模型的save方法会在末尾添加_1.

So when we try to create a publisher with name already exists, the save method of the model will add the _1 to the end.

当我们再次尝试使用相同的 name 创建新记录时，将引发 Integrity 错误，如下所示

And when we again try to create a new record with same name, an Integrity error will be raised as below

>> Publisher.objects.create(name="abc")
   result: slug will be "abc"
>> Publisher.objects.create(name="abc")
   result: slug will be "abc_1"
>> Publisher.objects.create(name="abc")
   result: 

     .................
     .................
     34     del cursor
     35     del connection
---> 36     raise errorclass, errorvalue
     37 
     38 re_numeric_part = re.compile(r"^(d+)")

IntegrityError: (1062, "Duplicate entry 'abc_1' for key 'slug'")

所以我想要的是，如果标题/slug 已经存在于数据库中，并且如果 slug 中包含数字(最后像 abc_1)，我们应该增加它的数字

So what i am want is if the title/slug already exists in the database and if slug contains number in it(at the end like abc_1), we should increment it that number

所以我想要的只是增加 slug 中的数字 如果标题/slug 已经存在于数据库中

So what all i want is to increment the number in the slug as below if the title/slug already exists in the database

abc
abc_1
abc_2
abc_3  

那么谁能告诉我如何实现上述增加 slug 的逻辑?

So can anyone please let me know how to implement the above logic of incrementing the slug ?

提前致谢......

推荐答案

你将不得不使用循环而不是一个单一的条件.试试这个:

You will have to use loop instead of just a one condition. Try this:

class Publisher(models.Model):
    name = models.CharField(max_length=200)
    slug = models.SlugField(max_length=150, unique=True)    

    def save(self, *args, **kwargs):
        if not self.id and not self.slug:
            slug = slugify(self.name)
            slug_exists = True
            counter = 1
            self.slug = slug
            while slug_exists:
                try:
                    slug_exits = Publisher.objects.get(slug=slug)
                    if slug_exits:
                        slug = self.slug + '_' + str(counter)
                        counter += 1
                except Publisher.DoesNotExist:
                    self.slug = slug
                    break
        super(Publisher, self).save(*args, **kwargs)

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