如何在 Scala 中的范围内进行模式匹配? [英] How can I pattern match on a range in Scala?

问题描述

在 Ruby 中我可以这样写:

In Ruby I can write this:

case n
when 0...5  then "less than five"
when 5...10 then "less than ten"
else "a lot"
end

如何在 Scala 中做到这一点?

How do I do this in Scala?

最好比使用 if 更优雅.

preferably I'd like to do it more elegantly than using if.

推荐答案

内部模式匹配可以用守卫表示:

Inside pattern match it can be expressed with guards:

n match {
  case it if 0 until 5 contains it  => "less than five"
  case it if 5 until 10 contains it => "less than ten"
  case _ => "a lot"
}

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