比较python中的两个dict以获得相似键的最大值 [英] comparing two dict in python to get the maximum value for similar key

问题描述

我有这两个字典:

a={"test1":90,  "test2":45,  "test3":67,  "test4":74}
b={"test1":32,  "test2":45,  "test3":82,  "test4":100}

如何提取同一键的最大值以获得新的字典，如下所示:

how to extract the maximum value for the same key to get new dict as this below:

c={"test1":90,  "test2":45,  "test3":82,  "test4":100}

推荐答案

你可以这样试试，

>>> a={"test1":90, "test2":45, "test3":67, "test4":74} 
>>> b={"test1":32, "test2":45, "test3":82, "test4":100}
>>> c = { key:max(value,b[key]) for key, value in a.iteritems() }
>>> c
{'test1': 90, 'test3': 82, 'test2': 45, 'test4': 100}

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