Javascript臭名昭著的循环问题? [英] Javascript infamous Loop issue?

查看:23
本文介绍了Javascript臭名昭著的循环问题?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

I've got the following code snippet.

function addLinks () {
    for (var i=0, link; i<5; i++) {
        link = document.createElement("a");
        link.innerHTML = "Link " + i;
        link.onclick = function () {
            alert(i);
        };
        document.body.appendChild(link);
    }
}

The above code is for generating 5 links and binding each link with an alert event to show the current link id. But It doesn't work. When you click the generated links they all say "link 5".

But the following code snippet works as our expectation.

function addLinks () {
    for (var i=0, link; i<5; i++) {
        link = document.createElement("a");
        link.innerHTML = "Link " + i;
        link.onclick = function (num) {
            return function () {
                alert(num);
            };
        }(i);
        document.body.appendChild(link);
    }
}

The above 2 snippets are quoted from here. As the author's explanation seems the closure makes the magic.

But how it works and How closure makes it work are all beyond my understanding. Why the first one doesn't work while the second one works? Can anyone give a detailed explanation about the magic?

解决方案

Quoting myself for an explanation of the first example:

JavaScript's scopes are function-level, not block-level, and creating a closure just means that the enclosing scope gets added to the lexical environment of the enclosed function.

After the loop terminates, the function-level variable i has the value 5, and that's what the inner function 'sees'.

In the second example, for each iteration step the outer function literal will evaluate to a new function object with its own scope and local variable num, whose value is set to the current value of i. As num is never modified, it will stay constant over the lifetime of the closure: The next iteration step doesn't overwrite the old value as the function objects are independant.

Keep in mind that this approach is rather inefficient as two new function objects have to be created for each link. This is unnecessary, as they can easily be shared if you use the DOM node for information storage:

function linkListener() {
    alert(this.i);
}

function addLinks () {
    for(var i = 0; i < 5; ++i) {
        var link = document.createElement('a');
        link.appendChild(document.createTextNode('Link ' + i));
        link.i = i;
        link.onclick = linkListener;
        document.body.appendChild(link);
    }
}

这篇关于Javascript臭名昭著的循环问题?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆