JSON对象数组到Java POJO [英] Array of JSON Object to Java POJO

问题描述

将此 JSON 对象转换为 java 中的类，映射将如何在您的 POJO 类中?

Converting this JSON object as a class in java, how would the mapping be in your POJO Class?

{
    "ownerName": "Robert",
    "pets": [
        {
            "name": "Kitty"
        },
        {
            "name": "Rex"
        },
        {
            "name": "Jake"
        }
    ]
}

推荐答案

这种问题很流行，需要一般性的回答.如果您需要基于 JSON 或 JSON Schema 生成 POJO 模型，请使用

This kind of question is very popular and needs general answer. In case you need generate POJO model based on JSON or JSON Schema use www.jsonschema2pojo.org. Example print screen shows how to use it:

使用方法:

1. 选择目标语言.Java 在你的情况下.
2. 选择来源.JSON 在你的情况下.
3. 选择注释样式.这可能很棘手，因为它取决于您要用于序列化/反序列化 JSON 的库.如果架构很简单，请不要使用注释(None 选项).
4. 选择其他可选配置选项，例如 包括 getter 和 setter.您也可以在 IDE 中执行此操作.
5. 选择预览按钮.如果架构很大，请下载带有生成类的 ZIP.

1. Select target language. Java in your case.
2. Select source. JSON in your case.
3. Select annotation style. This can be tricky because it depends from library you want to use to serialise/deserialise JSON. In case schema is simple do not use annotations (None option).
4. Select other optional configuration options like Include getters and setters. You can do that in your IDE as well.
5. Select Preview button. In case schema is big download ZIP with generated classes.

对于您的 JSON，此工具会生成:

For your JSON this tool generates:

public class Person {

 private String ownerName;
 private List <Pet> pets = null;

 public String getOwnerName() {
  return ownerName;
 }

 public void setOwnerName(String ownerName) {
  this.ownerName = ownerName;
 }

 public List < Pet > getPets() {
  return pets;
 }

 public void setPets(List < Pet > pets) {
  this.pets = pets;
 }

}

public class Pet {

 private String name;

 public String getName() {
  return name;
 }

 public void setName(String name) {
  this.name = name;
 }
}

对于 Android Studio 和 Kotlin 阅读 RIP http://www.jsonschema2pojo.org.

For Android Studio and Kotlin read RIP http://www.jsonschema2pojo.org.

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