类型'Any'在xcode 8 Swift 3中没有下标成员 [英] Type 'Any' Has no Subscript Members in xcode 8 Swift 3

查看:30
本文介绍了类型'Any'在xcode 8 Swift 3中没有下标成员的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

My App is supposed to go to a specific location to pull down the website it needs to load. In 2.3 it worked like a charm, but since I've updated xcode (which I don't have a ton of experience in) it is giving me the error "type 'Any' has no subscript members" and highlighting the "json" right before line three

...Retriever = json["WEB"]...

this is the code related to it.

let json = try JSONSerialization.jsonObject(with: data!, options:.allowFragments)

      if let Retriever = json["WEB"] as? [[String: AnyObject]] {

                 for website in Retriever {

                    if let name = website["URL"] as? String {

                          self.loadAddressURL(name)

I feel like I am missing something small. If there is a better way to do this, I would love suggestions. The URL returns this JSON

{
  "WEB" : [
           {
            "URL" : "http://www.google.com"
           }    
          ]
}

but I would love it if I could simplify it to just

{"URL":"http://www.google.com"}

解决方案

Try this:

let json = try JSONSerialization.jsonObject(with: data!, options:.allowFragments) as! [String:AnyObject]

Safe way:

do {
    if let json = try JSONSerialization.jsonObject(with: data!, options:.allowFragments) as? [String:Any] {
        print(json)
    }
} catch let err{
    print(err.localizedDescription)
}

You have to cast type Any to Swift dictionary type [String:AnyObject].

Edit: Swift 3
In swift 3 the purpose of AnyObject is more clarified. So more favourable Swift Dictionary type will be [String:Any].

Any is an alias for any data type.
AnyObject is an alias for any data type derived from a class.

For more info visit: https://craiggrummitt.com/2016/09/16/any-vs-anyobject-vs-nsobject-in-swift-3/

这篇关于类型'Any'在xcode 8 Swift 3中没有下标成员的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆