雪花中具有多个JSON对象的横向展平阵列 [英] Lateral flatten array with multiple JSON objects in Snowflake
本文介绍了雪花中具有多个JSON对象的横向展平阵列的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个包含多个JSON对象的数组。位于表中的任何JSON数组中的最大元素数为8。
以下是数组原始值的示例:
variants
----------------------------------------------------------------
[
{
"id": 12388362846279,
"inventory_quantity": 10,
"sku": "sku1"
},
{
"id": 12388391387207,
"inventory_quantity": 31,
"sku": "sku2"
},
{
"id": 12394420142151,
"inventory_quantity": 12,
"sku": "sku3"
},
{
"id": 12394426007623,
"inventory_quantity": 4,
"sku": "sku4"
},
{
"id": 12394429022279,
"inventory_quantity": 9,
"sku": "sku5"
},
{
"id": 12394431414343,
"inventory_quantity": 15,
"sku": "sku6"
},
{
"id": 12394455597127,
"inventory_quantity": 22,
"sku": "sku7"
},
{
"id": 12394459856967,
"inventory_quantity": 0,
"sku": "sku8"
}
]
我的查询尝试展平和解析数组,以便为每个对象返回一行:
select
variants[0]:sku,
variants[0]:inventory_quantity,
variants[1]:sku,
variants[1]:inventory_quantity,
variants[2]:sku,
variants[2]:inventory_quantity,
variants[3]:sku,
variants[3]:inventory_quantity,
variants[4]:sku,
variants[4]:inventory_quantity,
variants[5]:sku,
variants[5]:inventory_quantity,
variants[6]:sku,
variants[6]:inventory_quantity,
variants[7]:sku,
variants[7]:inventory_quantity
from table
, lateral flatten(input => variants)
但是,我的输出返回重复/重复的值:
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
我希望我的输出类似于以下内容:
+------+----+
| sku1 | 10 |
+------+----+
| sku2 | 31 |
+------+----+
| sku3 | 12 |
+------+----+
| sku4 | 4 |
+------+----+
| sku5 | 9 |
+------+----+
| sku6 | 15 |
+------+----+
| sku7 | 22 |
+------+----+
| sku8 | 0 |
+------+----+
推荐答案
使用横向展平消除了显式引用数组位置的需要。阵列的每个成员都成为其自己的行。因此,要获得上面想要的结果,只需使用:
select v.value:sku::varchar,
v.value:inventory_quantity
from table,
lateral flatten(input => table.variants) v
;
如果表中有您想要在每行引用的数组之外的列,只需将它们包括在SELECT中即可。从本质上讲,数组中的平坦行隐式地"联接"到表的非嵌套列……
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