调用的RenderAction错误的操作方法 [英] RenderAction calls wrong action method

问题描述

我与挣扎的RenderAction，问题是它调用了错误的操作方法我的控制器。

I'm struggling with renderaction, the problem is that it calls the wrong action method on my controller.

在我的用户控制器有两种操作方法调用的编辑，一个是get和一个POST请求：

On my "Users" controller there are two action methods called edit, one for get and one for post requests:

public virtual ActionResult Edit(int id)
{
 //return a view for editing the user
}


[AcceptVerbs(HttpVerbs.Post)]
public virtual ActionResult Edit(UserViewModel model)
{
 //modify the user...
}

在我看来，我打电话给它的RenderAction如下：

In my view, I'm calling Renderaction it as follows:

Html.RenderAction("Edit", "Users", new { id = 666});

现在的问题是，我想要呈现的GET操作方法。但是（也许是因为该机型还包含了一个名为ID？属性），调用的RenderAction我的POST操作方法，而不是。

Now the problem is that I want the GET action method to be rendered. However (perhaps because the model also contains a property called ID?), Renderaction calls my POST action method instead.

什么是做到这一点的正确方法？我使用ASP.NET MVC 3 RC在它的问题的情况下。

What's the proper way to do this? I'm using ASP.NET MVC 3 RC in case it matters.

谢谢，

阿德里安

推荐答案

问题是，你的看法是回发操作后所呈现。在视图中的所有子动作效果图使用相同的HTTP方法。所以POST正在复制他们。我不知道MVC3，但在MVC2有克服这个问题没有内置的方式。

Sub action uses HTTP method of its parent action

The problem is that your view is being rendered after a postback action. All sub-action renderings in the view use the same HTTP method. So POST is being replicated on them. I'm not sure about MVC3, but in MVC2 there was no built-in way to overcome this problem.

所以，问题是，你希望你的编辑（）操作呈现为一个POST视图GET。盒子外面。没办法。

So the problem is that you want your Edit() action to be rendered as a GET on a POST view. Out of the box. No way.

当然你也可以通过提供自己的功能=类做到这一点。

You can of course do it by providing your own functionality = classes.

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