PyQt5 QComboBox列表项更改位置 [英] PyQt5 QComboBox list items changing postion
本文介绍了PyQt5 QComboBox列表项更改位置的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我遇到了一些Qcombobox项目的显示样式问题。目前我硬编码的数据将显示在组合框中。
代码如下:
self.Dummy = QComboBox(self)
self.Dummy.setGeometry(200,600, 350, 50)
self.Dummy.setStyleSheet("QComboBox {background-color: white;border-style: outset;" border-width: 2px;border-radius: 5px;border-color: #448aff; font: 12px; min-width: 10em; padding: 3px;}")
self.Dummy.addItems(["-Select-", "2", "3","4","5","6","7","8","9","0","11",])
问题是,在每次选择后,下拉"列表"的位置都会不断变化。这是我面临的问题的图像。
下面是我的组合框
该列表包含项目<;-Select->,2,3,4,5,6,7,8,9,0,11,其中<;-选择->将是第一个显示的元素。 现在,当我单击该框时,框将列出元素,假设我选择了‘2’。然后,如果我尝试选择另一项,列表将以"向下"的方向放置。见下文 现在,假设从这些项中选择了最后一个元素‘11’。现在,如果我试图通过点击该框来选择一个新的项目,列表将被弹出"向上"而不是向下。见下文应该做些什么来修复它?我认为这不是样式表的问题,如果没有它,这个问题就会发生。我需要解决这个问题的原因是,当列表弹出时,它覆盖了上面的标签
推荐答案
您看到的是取决于操作系统和样式的行为。
要避免它,最好的方法是将QComboBox子类化并覆盖showPopup()
,然后调用基类实现(它负责显示弹出视图、调整大小和定位),并在必要时移动它。
class Combo(QtWidgets.QComboBox):
def showPopup(self):
super().showPopup()
# find the widget that contains the list; note that this is *not* the view
# that QComboBox.view() returns, but what is used to show it.
popup = self.view().window()
rect = popup.geometry()
if not rect.contains(self.mapToGlobal(self.rect().center())):
# the popup is not over the combo, there's no need to move it
return
# move the popup at the bottom left of the combo
rect.moveTopLeft(self.mapToGlobal(self.rect().bottomLeft()))
# ensure that the popup is always inside the edges of the screen
# we use the center of the popup as a reference, since with multiple
# screens the combo might be between two screens, but that position
# could also be completely outside the screen, so the cursor position
# is used as a fallback to decide on what screen we'll show it
done = False
for i, pos in enumerate((rect.center(), QtGui.QCursor.pos())):
for screen in QtWidgets.QApplication.screens():
if pos in screen.geometry():
screen = screen.geometry()
if rect.x() < screen.x():
rect.moveLeft(screen.x())
elif rect.right() > screen.right():
rect.moveRight(screen.right())
if rect.y() < screen.y():
rect.moveTop(screen.y())
elif rect.bottom() > screen.bottom():
# if the popup goes below the screen, move its bottom
# *over* the combo, so that the its current selected
# item will always be visible
rect.moveBottom(self.mapToGlobal(QtCore.QPoint()).y())
done = True
break
if done:
break
popup.move(rect.topLeft())
这也可以在没有子类化的情况下完成(例如,如果您有许多组合,您从Designer创建了UI,并且不想使用提升的小部件),但您必须记住更改对组合的所有引用。
class MyWindow(QtWidgets.QWidget):
def __init__(self):
# ...
self.combo = QtWidgets.QComboBox()
self.combo.showPopup = self.showPopupAndCheck
def showPopupAndCheck(self):
QtWidgets.QComboBox.showPopup(self.combo)
popup = self.view().window()
rect = popup.geometry()
if not rect.contains(self.combo.mapToGlobal(self.combo.rect().center())):
# the popup is not over the combo, there's no need to move it
return
# change everything from self to self.combo
或者,如果您希望在所有程序中保持此行为的一致性,而不总是使用子类,您可以使用某种猴子修补黑客。
优点在于,您创建的任何QComboBox(即使在运行时加载UI文件或创建组合框)都将始终使用新行为。
重要信息:此必须位于程序的主文件的最开始位置,可能就在导入部分之后。
from PyQt5 import QtCore, QtGui, QtWidgets
def customShowPopup(self):
# we can't use super(), because we're not in the class definition, but
# calling the class method with "self" as first argument is practically the
# same thing; note the underscore!
QtWidgets.QComboBox._showPopup(self)
popup = self.view().window()
# ... go on, exactly as above
# create a new reference to the showPopup method, which is the one we've used
# in the function above
QtWidgets.QComboBox._showPopup = QtWidgets.QComboBox.showPopup
# overwrite the original reference with the new function
QtWidgets.QComboBox.showPopup = customShowPopup
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